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Chapter 4: Problem 9

Maltotriose is a trisaccharide composed of three glucose molecules linked through \(\alpha-1,4\) glycosidic linkages formed via dehydration synthesis. What would the formula be for maltotriose? (A) \(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{18}\) (B) \(\mathrm{C}_{18} \mathrm{H}_{10} \mathrm{O}_{15}\) (C) \(\mathrm{C}_{18} \mathrm{H}_{32} \mathrm{O}_{16}\) (D) \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{3}\)

Short Answer

Expert verified
The formula for maltotriose is (C) \(\mathrm{C}_{18} \mathrm{H}_{32} \mathrm{O}_{16}\).

Step by step solution

01

Determine the total number of atoms in three glucose molecules

In order to determine the molecular formula for maltotriose, first, we will find out the total number of carbon, hydrogen, and oxygen atoms in three glucose molecules. Since the molecular formula for glucose is \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\), for three glucose molecules, it would be: Carbon atoms: \(6 \times 3 = 18\) Hydrogen atoms: \(12 \times 3 = 36\) Oxygen atoms: \(6 \times 3 = 18\) So, the combined formula for three glucose molecules is \(\mathrm{C}_{18} \mathrm{H}_{36} \mathrm{O}_{18}\).
02

Subtract water molecules lost due to dehydration synthesis

Since maltotriose is formed by linking three glucose molecules with \(\alpha-1,4\) glycosidic linkages formed via dehydration synthesis, it involves the loss of water molecules. For every linkage formed, one water molecule is lost. As there are two linkages in maltotriose (to connect three glucose molecules), there will be a loss of two water molecules (\(\mathrm{H}_{2} \mathrm{O}\)). Subtract the lost water molecules from the combined formula of three glucose molecules: Carbon atoms remain the same: \(18\) Hydrogen atoms: \(36 - 2 \times 2 = 32\) Oxygen atoms: \(18 - 2 = 16\)
03

Write the molecular formula for maltotriose

The molecular formula for maltotriose after removing the water molecules lost due to dehydration synthesis is: \(\mathrm{C}_{18} \mathrm{H}_{32} \mathrm{O}_{16}\) Hence, the correct answer is (C) \(\mathrm{C}_{18} \mathrm{H}_{32} \mathrm{O}_{16}\).

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Most popular questions from this chapter

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