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Chapter 12: Q. 30 (page 328)

Use the probability method to calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc parents

Short Answer

Expert verified

As a result, the ratios are 1:1:1:1.

Step by step solution

01

Step. 1 Introduction

A genotype is a series of genes that encode in a particular individual's genetic characteristics. The genotypic ratio refers to the ratio that depicts the various genotypes of children out of a test cross.

02

Step. 2 Explanation

You fully understand the genomes of the parents, where you need to differentiate into pair of alleles, both genes, for the cross. AABBCc is divided similarly to ABC and ABc. Aabbcc is divided similarly to Abc and abc. You can now cross them, and the probabilities are: AABbCc, AaBbCc, AABbcc, & AaBbcc. So, 25% of the progeny would be AaBbCc, 25% would be AaBbcc, 25% would be AABbCc, and 25% will be AABbcc.

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Most popular questions from this chapter

Figure 12.12 What ratio of offspring would result from a cross between a white-eyed male and a female that is heterozygous for red eye color?

Can a human male be a carrier of red-green color blindness?

Explain epistasis in terms of its Greek-language roots “standing upon.”

Which of the following situations does not follow the Law of Independent Assortment?

a. A blind man and a brunette woman produce three offspring over time, all of who have blind hair.

b. A white cow crossed with a brown bull produces roan cattle.

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A recessive trait will be observed in individuals that are ________ for that trait.

a. heterozygous

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