Assume you are mapping genes A, B, C, and D in Drosophila. You know that these genes are linked on the same chromosome, and you determine the recombination frequencies between each pair of genes to be as follows: A-B, 8%; A-C, 28%; A-D, 25%; B-C, 20%; B-D, 33%.

  1. Describe how you determined the recombination frequency for each pair of genes.

  2. Draw a chromosome map based on your data.

Short Answer

Expert verified

(a). An F1 dihybrid offspring for each pair of genes is generated to obtain recombinant frequencies. The F1 hybrid is then test crossed with a homozygous recessive fly. The parental and recombinant offspring are observed and counted to determine the recombination frequency between the two genes.

(b).

Step by step solution

01

Recombination frequency

The number of recombinants produced concerning the number of offspring in a cross is referred to as recombinant frequency.The recombination frequency between gene pairs helps to calculate the distance between the genes on a chromosome.

1% recombinant frequency refers to one map unit. The distance between the genes on the chromosome is referred to as map units.

02

Calculation of recombinant frequency between the pair of genes

Calculate the recombinant frequency for geneAand geneB. First, a homozygous dominant parent (AABB) is crossed with a recessive parent (aabb). The offspring produced would be F1dihybrid with genotypeAbBb.

The F1dihybrid is then test crossed with a homozygous recessive fly (aabb).The offspring produced from this cross is observed and segregated as parental and recombinants based on parents' genotype.

The recombination frequency between the gene pairs is calculated using the formula:

RecombinantFrequency=NumberofrecombinantsTotalnumberofoffspring×100

03

Chromosome map

According to the given data, the distance between geneAand geneBis 8 map units, betweenAandCis 28 map units, betweenAandDis 25 map units, betweenBandCis 20 map units, and betweenAandDgene is 33 map units.

The data suggest that gene A and B is located between gene D and C. Therefore, the sequence of genes on the chromosome is DABC.

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Most popular questions from this chapter

The continuity of life is based on heritable information in the form of DNA. In a short essay (100-150 words), relate the structure and behavior of chromosomes to inheritance in both asexually and sexually reproducing species.

The results in the data table are from a simulated F1 dihybrid test cross. The hypothesis that the two genes are unlinked predicts that the offspring phenotypic ratio will be 1:1:1:1. Using this ratio, calculate the expected number of each phenotype out of the 900 total offspring, and enter the values in that data table.

About 5% individuals with Down syndrome have a chromosomal translocation in which a third copy of chromosome 21 is attached to chromosome 14. If this translocation occurred in a parent’s gonad, how could it lead to Down syndrome in a child?

Two genes of a flower, one controlling blue (B) versus white (b) petals and the other controlling round (R) versus oval (r) stamens, are linked and are 10 map units apart. You cross a homozygous blue oval plant with a homozygous white round plant. The resulting F1 progeny are crossed with homozygous white oval plants, and 1,000 offspring plants are obtained. How many plants of each of the four phenotypes do you expect?

A wild-type fly (heterozygous for gray body and normal wings) is mated with a black fly with vestigial wings. The offspring have the following phenotypic distribution: wild type, 778; black vestigial; 785; black normal, 158; gray vestigial, 162. What is the recombination frequency between these genes for the body color and wing size? Is this consistent with the results of the experiment in Figure 15.9?

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