You design Drosophila crosses to provide recombination data for genes a, which is located on the chromosome shown in Figure 15.12. Gene a has recombination frequencies of 14% with the vestigial wing locus and 26% with the brown eye locus. Approximately where is a located along the chromosome?

Short Answer

Expert verified

Gene a is located one-third from the vestigial wing locus to the brown eye locus.

Step by step solution

01

Distance between vestigial wing locus and brown eye locus

The gene for the vestigial wing is located at 67.0 map units, and that of brown eyes is 104.5 map units from the aristae locus. Thus,the distance between these genes is the difference in their map units.

Thus, the distance between the two genes is 37.5 map units (104.5-67.0).

02

Position of gene a on the chromosome

The recombination frequency of geneawith vestigial wing locus is 14%, and that of brown eye locus is 26%.The distance between the genes for the vestigial wing and brown eye is 37.5.

However, none of the gene frequencies is greater than 37.5%. This suggests that the gene a must be located between the vestigial wing locus and brown eye locus.

03

Position of gene a between the vestigial wing locus and brown eye locus

One percent recombination frequency corresponds to one map unit.The geneais located 14 map units right from the vestigial wing locus because the recombination frequency of geneawith vestigial wing locus is 14%.

Similarly, geneais located 26 map units left from the brown eye locus because the recombination frequency of geneawith brown eye locus is 26%. Thus,geneais 14 map units far from the vestigial wing locus, which is almost half the distance from the brown eye locus (26 map units).

This suggests that gene a is located one-third from the vestigial wing locus to the brown eye locus.

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Most popular questions from this chapter

Gene A, B, and C are located on the same chromosome. Test crosses show that the recombination frequency between A and B is 28% and that between A and C is 12%. Can you determine the linear order of these genes?

Assume that genes A and B are on the same chromosome and are 50 map units apart. An animal heterozygous at both loci is crossed with one that is homozygous recessive at both loci. What percentage of the offspring will show recombinant phenotypes resulting from crossover? Without knowing these genes are on the same chromosome, how would you interpret the results of this cross?

The goodness of fit is measured by\({\chi ^{^2}}\). This statistic measures the amounts by which the observed values differ from their respective predictions to indicate how closely the two sets of values match. The formula for calculating this value is

\({\chi ^{}} = \sum \frac{{{{\left( {o - e} \right)}^2}}}{e}\)

Where o=observed and e= expected. Calculate the\({\chi ^{^2}}\)value for the data using the table below. Fill out the table, carrying out the operations indicated in the top row. Then add up the entries in the last column to find the\({\chi ^{^2}}\)value.

Testcross Offspring

Expected

(e)

Observed

(o)

Deviation

(o-e)

(o-e)2

(o-e)2/e

(A-B-)

220

(aaB-)

210

(A-bb)

231

(aabb)

239

\({\chi ^2}\) =sum

When two genes are located on the same chromosome, what is the physical basis for the production of recombinant offspring in a testcross between a dihybrid parent and a double-mutant (recessive) parent?

Neither Tim nor Rhoda had Duchenne muscular dystrophy, but their firstborn son does. What is the probability that a second child will have the disease? What is the probability if the second child is a boy? A girl?

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