Given a polynucleotide sequence such as GAATTC. Explain what further information you would need in order to identify which is the 5’ end. (See Figure 16.5)

Short Answer

Expert verified

Out of the two ends of the DNA molecule, the end with a phosphate group on the 5’ carbon of the sugar is called the 5’ end of the DNA. Thus, the 5’ end of the DNA molecule cannot be identified with the nucleotide sequence.

Step by step solution

01

Structure of DNA molecule

DNA is a polymer of nucleotide molecule. Each nucleotide comprises three components: a pentose sugar (2-deoxy-D-ribose), a phosphate group, and a heterocyclic base. Purine and pyrimidines are two classes of bases found in DNA.

In each nucleotide, the phosphate group is attached to the 5’ C of the sugar moiety, and the nitrogen base is attached to the 1’ C of sugar. A phosphodiester bond links the nucleotides in the DNA molecule.

The phosphate group of one nucleotide forms a covalent bond with the 3’ C of the pentose sugar of the adjacent nucleotide forming the polynucleotide sequence.

02

Polarity of DNA molecule

DNA is a double-helical molecule as it comprises two strands. The two strands of the molecule have opposite polarity. This is because the ends of the two strands are different. One strand ends with the phosphate group on the 5’ end of the sugar; this end is called the 5’ end of carbon.

The other strand ends with the OH group on the 3’ carbon of the sugar; this end is called the 3’ end. One strand runs in a 5’ to 3’ direction and the other in a 3’ to 5’ direction. Thus, the end of the DNA molecule has both 5’ and 3’ends. As a result, the two strands of DNA molecules are anti-parallel.

03

To determine the 5’ end of DNA    

To identify the 5’ end of DNA, one must know the end of the DNA molecule with a phosphate group attached to 5’C of the sugar. This is because the phosphate group at 5’C marks the 5’ end of the DNA molecule, and the OH group at 3’C marks the 3’ end of DNA.

Thus, to know the DNA molecule’s 3’ or 5’ ends, one must know the phosphate or OH group present at the end of each strand.

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Most popular questions from this chapter

The spontaneous loss of amino groups from adenine in DNA results in hypoxanthine, an uncommon base, opposite thymine. What combination of proteins could repair such damage?

  1. nuclease, DNA polymerase, DNA ligase
  2. telomerase, primase, DNA polymerase
  3. telomerase, helicase, single-stranded binding protein
  4. DNA ligase, replication fork proteins, adenylyl cyclase

What role does complementary base pairing play in the replication of DNA?

The elongation of the leading strand during DNA synthesis

  1. progress away from the replication fork.
  2. occurs in the 35direction.
  3. produces Okazaki fragments.
  4. depends on the action of DNA polymerase.

E.coli grown on a 15N medium is transferred to a 14N medium and allowed to grow for two more generations (two rounds of DNA replication). DNA extracted from these cells is centrifuged. What density distribution of DNA would you expect in this experiment?

  1. one high-density and one low-density band
  2. one intermediate density band
  3. one high density and one intermediate-density band
  4. one low-density and one intermediate-density band

: If Chargaff's rule—that the amount of A equals the amount of T and the amount of C equals the amount of G—is valid, then hypothetically, we could extrapolate this to the combined DNA of all species on Earth (like one huge Earth genome). To see whether the data in the table support this hypothesis, calculate the average percentage for each base in your completed table by averaging the values in each column. Does Chargaff's equivalence rule still hold true?

Source of DNA

Base Percentage

Adenine

Guanine

Cytosine

Thymine

Sea urchin

32.8

17.7

17.3

32.1

Salmon

29.7

20.8

20.4

29.1

Wheat

28.1

21.8

22.7

27.4

E. coli

24.7

26.0

25.3

24.0

Human

30.4

19.8

19.8

30.1

Ox

29.0

21.0

21.0

29.0

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