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Chapter 4: Problem 32

Predict the \(F_{1}\) and \(F_{2}\) results of crossing a male fowl that is cock- feathered with a true-breeding hen-feathered female fowl. Recall that these traits are sex limited.

Short Answer

Expert verified
Answer: If the male fowl is homozygous dominant (CC), then all offspring will be cock-feathered. If the male fowl is heterozygous (CH), then 50% of the offspring will be cock-feathered, and 50% of the offspring will be hen-feathered.

Step by step solution

01

Determine the genotypes of the parents

Use the abbreviations C (cock-feathered allele) and H (hen-feathered allele). Since the male is cock-feathered, he has either the CC or CH genotype. Since the female is true-breeding hen-feathered, she must have the HH genotype. Case 1: Male is CC (homozygous dominant) Father: CC Mother: HH Case 2: Male is CH (heterozygous) Father: CH Mother: HH
02

Set up Punnett squares for both cases

Now, let's set up two Punnett squares, one for each case. Case 1: | C | C | H| | | H| | | Case 2: | C | H | H| | | H| | |
03

Fill in the Punnett squares

Fill in the Punnett squares with the possible offspring genotypes resulting from the given parental genotypes. Case 1: | C | C | H| CH | CH | H| CH | CH | Case 2: | C | H | H| CH | HH | H| CH | HH |
04

Determine the phenotypes of offspring

Based on the genotypes in the Punnett squares, determine the phenotypes of the offspring for each case. Case 1: All offspring have the CH genotype, which means that all offspring will have cock-feathering. Case 2: Since cock-feathering is dominant, any offspring with the CH genotype (50% of the offspring) will be cock-feathered. The other 50% of the offspring, with the HH genotype, will display hen-feathering.
05

Predict the F1 and F2 results based on the two cases

Finally, let's predict the offspring for each case. If the male fowl is CC, then all offspring will be cock-feathered (F1). In the second case, if the male fowl is CH, then 50% of the offspring will be cock-feathered (F1), and 50% of the offspring will be hen-feathered (F2).

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Most popular questions from this chapter

A husband and wife have normal vision, although both of their fathers are red- green color-blind, an inherited X-linked recessive condition. What is the probability that their first child will be (a) a normal son? (b) a normal daughter? (c) a color-blind son? (d) a color- blind daughter?

Another recessive mutation in Drosophila, ebony \((e),\) is on an autosome (chromosome 3) and causes darkening of the body compared with wild-type flies. What phenotypic \(F_{1}\) and \(F_{2}\) male and female ratios will result if a scalloped-winged female with normal body color is crossed with a normal-winged cbony male? Work out this problem by both the Punnett square method and the forked-line method.

Karl Landsteiner and Philip Levine discovered a glycoprotein expressed on the surface of red blood cells, which exists in two forms, \(M\) and \(N .\) An individual may produce either one or both of them. The alleles \(L^{M}\) and \(L^{N}\) control the expression of the glycoprotein. What type of inheritance does the MN blood group exhibit, and what are the genotypes of the phenotypes observed in the human population?

As in Problem \(12,\) flower color may be red, white, or pink, and flower shape may be personate or peloric. For the following crosses, determine the \(P_{1}\) and \(F_{1}\) genotypes: (a) red, peloric \(\times\) white, personate 1 \(\mathrm{F}_{1}:\) all pink, personate (b) red, personate \(\times\) white, peloric 1 \(\mathrm{F}_{1}:\) all pink, personate (c) pink, personate \(\times\) red, peloric $\rightarrow \mathrm{F}_{1} \quad\left\\{\begin{array}{l}1 / 4 \mathrm{red}, \text { personate } \\ 1 / 4 \mathrm{red}, \text { peloric } \\ 1 / 4 \mathrm{pink}, \text { peloric } \\\ 1 / 4 \mathrm{pink}, \text { personate }\end{array}\right.$ (d) pink, personate \(\times\) white, peloric $\rightarrow \mathrm{F}_{1}\left\\{\begin{array}{l}1 / 4 \text { white, personate } \\ 1 / 4 \text { white, peloric } \\ 1 / 4 \text { pink, personate } \\ 1 / 4 \text { pink, peloric }\end{array}\right.$ (c) What phenotypic ratios would result from crossing the \(\mathrm{F}_{1}\) of (a) to the \(F_{1}\) of \((b) ?\)

In Drosophila , the \(\mathrm{X}\) -linked recessive mutation vermilion \((v)\) causes bright red eyes, in contrast to the brick-red eyes of wild type. A separate autosomal recessive mutation, suppressor of vermilion \((s u-v),\) causes flies homozygous or hemizygous for \(v\) to have wild-type eyes. In the absence of vermilion alleles, \(s u-v\) has no effect on eye color. Determine the \(\mathrm{F}_{1}\) and \(\mathrm{F}_{2}\) phenotypic ratios from a cross between a female with wild-type alleles at the vermilion locus, but who is homozygous for \(s u-v,\) with a vermilion male who has wild-type alleles at the \(s u-v\) locus.
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