The following \(F_{2}\) results occur from a typical dihybrid cross: $$\begin{array}{lll} \text { purple: } & A_{-} B_{-} & 9 / 16 \\ \text { white: } & a a B_{-} & 3 / 16 \\ \text { white: } & A_{-} b b & 3 / 16 \\ \text { white: } & a a b b & 1 / 16 \end{array}$$ If a double heterozygote \((A a B b)\) is crossed with a fully recessive organism (aabb), what phenotypic ratio is expected in the offspring?

Short Answer

Expert verified
Solution: The expected phenotypic ratio of purple to white in the offspring from this cross is \(\frac{9}{16} : \frac{7}{16}\).

Step by step solution

01

Set up the Punnett square

Since we have a dihybrid cross with two traits, we will create a Punnett square with 4 rows and 4 columns. Each row will represent the possible gametes from the double heterozygote parent (AaBb), and each column will represent the possible gametes from the fully recessive parent (aabb).
02

Determine the possible gametes of each parent

For the double heterozygote parent (AaBb), there are four possible gametes: AB, Ab, aB, and ab. For the fully recessive parent (aabb), there is only one possible gamete: ab.
03

Fill in the Punnett square

Now we will fill in the Punnett square by combining the gametes of each parent. $$ \begin{array}{c|c|c|c|c|} \multicolumn{1}{c}{\text {} } & \multicolumn{1}{c}{\text {a}} & \multicolumn{1}{c}{\text {a}} & \multicolumn{1}{c}{\text {b}} & \multicolumn{1}{c}{\text {b }} \\ \cline{2-5} \text {A} & Aa & Aa &\text {B} & Bb \\ \cline{2-5} \text {A} & Aa & Aa &\text {b} & Bb \\ \cline{2-5} \text {a} & aa & aa &\text {B} & Bb \\ \cline{2-5} \text {a} & aa & aa &\text {b} & bb \\ \cline{2-5} \end{array} $$
04

Calculate the phenotypic ratio

Analyzing the Punnett square, we can see the following genotypes for the offspring: - AABB: 1 (purple) - AABb: 2 (purple) - AaBB: 2 (purple) - AaBb: 4 (purple) - aaBb: 2 (white) - AAbb: 2 (white) - aabb: 1 (white) Now we can calculate the phenotypic ratio of purple to white. There are a total of 16 offspring in the Punnett square. 9 of them have a purple phenotype, and 7 have a white phenotype. So, the expected phenotypic ratio of purple to white in the offspring is \(\frac{9}{16} : \frac{7}{16}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Punnett Square
The Punnett square is a visual tool in genetics used to predict the possible genotypes of offspring from a cross between two parents. In a dihybrid cross, like the one provided in the exercise, we're examining two distinct traits, each represented by a different gene. For a parent with the genotype AaBb, which is heterozygous for both traits, the possible gametes are AB, Ab, aB, and ab.

These combinations are listed on one side of a 4x4 Punnett square, mirroring the unique pairing possibilities these gametes have with those from the other parent. If the other parent is homozygous recessive (aabb), then their only possible gamete is ab, which occupies the opposite side of the Punnett square.

Once the Punnett square is set up, we fill it in by combining each gamete from one parent with each gamete from the other parent. This step-by-step approach visualizes the probabilities of genotypes for each offspring. Even though the math behind the Punnett square is simple probabilities, it greatly enhances our understanding of how traits are passed down.
Phenotypic Ratio
The phenotypic ratio describes the proportion of offspring with different traits that result from a genetic cross. It's determined by examining the offspring's outward characteristics (phenotypes) rather than their genetic makeup (genotypes). In the provided exercise, we're comparing two phenotypes: purple and white.

After filling out the Punnett square and identifying the genotypes, we translate these into phenotypes based on dominance relationships. In the case of the A and B alleles, the dominant allele masks the presence of the recessive allele, leading to the purple phenotype whenever one or more dominant alleles (A or B) are present.

By calculating how many squares within the Punnett square represent each phenotype, we can establish the phenotypic ratio. It's important to recognize that while the genotypic ratio can be complex in a dihybrid cross due to multiple gene interactions, the phenotypic ratio simplifies this complexity into observable results.
Genetics
Genetics is the study of heredity and variation in living organisms. It explains how traits are passed from parents to offspring through genes. Genes, which are made up of DNA, act as instructions for making molecules called proteins.

In sexual reproduction, organisms inherit two sets of genes, one from each parent. These genes come in different variants, called alleles, which can be dominant or recessive. The combination of alleles determines an individual's genotype. The genotype, along with environmental factors, then influences the phenotype—the observable traits.

The exercise we've been looking at involves a dihybrid cross, which looks at the inheritance of two different genes. Genetics helps us understand the outcome of such crosses, predicting traits of offspring and allowing us to delve into the probabilities and patterns of inheritance, a fundamental aspect of biology.

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Most popular questions from this chapter

While vermilion is X-linked in Drosophila and causes the eye color to be bright red, brown is an autosomal recessive mutation that causes the eye to be brown. Flies carrying both mutations lose all pigmentation and are white-eyed. Predict the \(\mathrm{F}_{1}\) and \(\mathrm{F}_{2}\) results of the following crosses: (a) vermilion females \(\times\) brown males (b) brown females \(\times\) vermilion males (c) white females \(\times\) wild-type males

As in Problem \(12,\) flower color may be red, white, or pink, and flower shape may be personate or peloric. For the following crosses, determine the \(P_{1}\) and \(F_{1}\) genotypes: (a) red, peloric \(\times\) white, personate 1 \(\mathrm{F}_{1}:\) all pink, personate (b) red, personate \(\times\) white, peloric 1 \(\mathrm{F}_{1}:\) all pink, personate (c) pink, personate \(\times\) red, peloric $\rightarrow \mathrm{F}_{1} \quad\left\\{\begin{array}{l}1 / 4 \mathrm{red}, \text { personate } \\ 1 / 4 \mathrm{red}, \text { peloric } \\ 1 / 4 \mathrm{pink}, \text { peloric } \\\ 1 / 4 \mathrm{pink}, \text { personate }\end{array}\right.$ (d) pink, personate \(\times\) white, peloric $\rightarrow \mathrm{F}_{1}\left\\{\begin{array}{l}1 / 4 \text { white, personate } \\ 1 / 4 \text { white, peloric } \\ 1 / 4 \text { pink, personate } \\ 1 / 4 \text { pink, peloric }\end{array}\right.$ (c) What phenotypic ratios would result from crossing the \(\mathrm{F}_{1}\) of (a) to the \(F_{1}\) of \((b) ?\)

In Drosophila , the \(\mathrm{X}\) -linked recessive mutation vermilion \((v)\) causes bright red eyes, in contrast to the brick-red eyes of wild type. A separate autosomal recessive mutation, suppressor of vermilion \((s u-v),\) causes flies homozygous or hemizygous for \(v\) to have wild-type eyes. In the absence of vermilion alleles, \(s u-v\) has no effect on eye color. Determine the \(\mathrm{F}_{1}\) and \(\mathrm{F}_{2}\) phenotypic ratios from a cross between a female with wild-type alleles at the vermilion locus, but who is homozygous for \(s u-v,\) with a vermilion male who has wild-type alleles at the \(s u-v\) locus.

In goats, the development of the beard is due to a recessive gene. The following cross involving true-breeding goats was made and carried to the \(\mathrm{F}_{2}\) generation: Offer an explanation for the inheritance and expression of this trait, diagramming the cross. Propose one or more crosses to test your hypothesis.

Karl Landsteiner and Philip Levine discovered a glycoprotein expressed on the surface of red blood cells, which exists in two forms, \(M\) and \(N .\) An individual may produce either one or both of them. The alleles \(L^{M}\) and \(L^{N}\) control the expression of the glycoprotein. What type of inheritance does the MN blood group exhibit, and what are the genotypes of the phenotypes observed in the human population?

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