In four o'clock plants, many flower colors are observed. In a cross involving two true-breeding strains, one crimson and the other white, all of the \(F_{1}\) generation were rose color. In the \(F_{2}\) four new phenotypes appeared along with the \(P_{1}\) and \(F_{1}\) parental colors. The following ratio was obtained: Propose an explanation for the inheritance of these flower colors.

Short Answer

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The inheritance of flower colors in the cross between the true-breeding strains of four o'clock plants can be explained through the interaction of two independently inherited gene pairs (A and a; B and b). Crimson (AABB) and white (aabb) parents cross resulting in all F1 progeny being heterozygous (AaBb) with rose color flowers. Upon self-pollination of F1 progeny, the F2 generation shows a ratio of 1 crimson: 4 rose: 6 evening: 4 pink: 1 white, as determined by various combinations of the gene pairs A, a, B, and b. The principles of Mendelian genetics, such as the laws of segregation and independent assortment, help explain this inheritance pattern.

Step by step solution

01

Understand the inheritance pattern

We are given a cross between two true-breeding strains, one with crimson flowers and the other with white flowers. All of the F1 generation were rose color. This indicates that there is at least partial dominance of one trait over the other (crimson flower color partially dominates white flower color). In the F2 generation, different phenotypes appeared along with the parental colors. This suggests that there might be a more complex interaction between the genes than simple dominance.
02

Analyze the given ratio

The given ratio in the F2 generation is 1 crimson:4 rose:6 evening:4 pink:1 white. We can match these phenotypes to gene combinations using the law of segregation and the law of independent assortment. It seems that there might be two gene loci that are involved in the determination of flower color. Let's assume the two loci are A and B. The crimson phenotype can be coded as AABB, the white phenotype as aabb. Now we need to find the genotypes for rose, evening, and pink flower colors considering the mixture of alleles.
03

Propose a theoretical explanation

Based on the given ratio, we can propose an explanation using a hypothesis of gene interactions. We can assume that the color of flowers is determined by the interaction of two independently inherited gene pairs (A and a; B and b). The crimson parent (AABB) and the white parent (aabb) cross, and all the F1 progeny are heterozygous for both gene pairs (AaBb) and produce rose color flowers. Next, the F1 rose plants (AaBb) are allowed to self-pollinate, and the F2 progeny will have the following genotypes and phenotypes: - AABB: 1/16 crimson - AABb, AaBB, AAbb, aaBB: 4/16 rose - AaBb: 6/16 evening - Aabb, aabb, aaBb: 4/16 pink - aabb: 1/16 white The ratio in the F2 generation is 1 crimson: 4 rose: 6 evening: 4 pink: 1 white, as observed in the exercise. Using the principles of Mendelian genetics, we were able to explain the inheritance of flower colors in this cross.

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Most popular questions from this chapter

In rabbits, a series of multiple alleles controls coat color in the following way: \(C\) is dominant to all other alleles and causes full color. The chinchilla phenotype is due to the \(c^{\mathrm{ch}}\) allele, which is dominant to all alleles other than \(C\). The \(c^{h}\) allele, dominant only to \(c^{a}\) (albino), results in the Himalayan coat color. Thus, the order of dominance is \(C>c^{\mathrm{dh}}>c^{h}>c^{a} .\) For each of the fol- lowing three cases, the phenotypes of the \(\mathrm{P}_{1}\) generations of two crosses are shown, as well as the phenotype of one member of the \(\mathrm{F}_{1}\) generation. For each case, determine the genotypes of the \(P_{1}\) generation and the \(\mathrm{F}_{1}\) offspring, and predict the results of making each indicated cross between \(F_{1}\) individuals.

Review the Chapter Concepts list on page \(104 .\) These all relate to exceptions to the inheritance patterns encountered by Mendel. Write a short essay that explains why multiple and lethal alleles often result in a modification of the classic Mendelian monohybrid and dihybrid ratios.

In a disputed parentage case, the child is blood type \(\mathrm{O},\) while the mother is blood type \(A .\) What blood type would exclude a male from being the father? Would the other blood types prove that a particular male was the father?

Karl Landsteiner and Philip Levine discovered a glycoprotein expressed on the surface of red blood cells, which exists in two forms, \(M\) and \(N .\) An individual may produce either one or both of them. The alleles \(L^{M}\) and \(L^{N}\) control the expression of the glycoprotein. What type of inheritance does the MN blood group exhibit, and what are the genotypes of the phenotypes observed in the human population?

In this chapter, we focused on extensions and modifications of Mendelian principles and ratios. In the process, we encountered many opportunities to consider how this information was acquired. On the basis of these discussions, what answers would you propose to the following fundamental questions? (a) How were early geneticists able to ascertain inheritance patterns that did not fit typical Mendelian ratios? (b) How did geneticists determine that inheritance of some phenotypic characteristics involves the interactions of two or more gene pairs? How were they able to determine how many gene pairs were involved? (c) How do we know that specific genes are located on the sex-determining chromosomes rather than on autosomes? (d) For genes whose expression seems to be tied to the sex of individuals, how do we know whether a gene is X-linked in contrast to exhibiting sex-limited or sex-influenced inheritance?

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