A backcross was set up between two homozygous laboratory mouse strains \(A\) and \(B\), with the \(F_{1}\) backcrossed to \(B\). The \(F_{2}\) were typed using \(\operatorname{SNPs} x\) and \(y,\) which varied between strains \(A\) and \(B\left(x^{A}, x^{B}, y^{A}, y^{B}\right) .\) Out of 100 mice, 38 were \(x^{A} y^{A}, 40\) were \(x^{B} y^{B}, 11\) were \(x^{A} y^{B},\) and 11 were \(x^{B} y^{A} .\) What is the genetic distance between SNPs \(x\) and \(y ?\)

Short Answer

Expert verified
Answer: The genetic distance between SNPs x and y is 22 centimorgans.

Step by step solution

01

Determine parental and recombinant genotypes

First, let's identify the parental and recombinant genotypes in the given data: Parental genotypes: - 38 mice with \(x^{A}y^{A}\) - 40 mice with \(x^{B}y^{B}\) Recombinant genotypes: - 11 mice with \(x^{A}y^{B}\) - 11 mice with \(x^{B}y^{A}\) In total, there are 100 mice in the F2 generation.
02

Calculate the recombination frequency

The recombination frequency is the proportion of recombinant genotypes among all genotypes. To find this, we will divide the total number of recombinant offspring (mice with \(x^{A}y^{B}\) and \(x^{B}y^{A}\)) by the total number of offspring (100 mice). Recombination frequency = \(\frac{11 + 11}{100} = \frac{22}{100} = 0.22\)
03

Convert the recombination frequency to genetic distance in centimorgans (cM)

To convert the recombination frequency to the genetic distance in centimorgans (cM), multiply the recombination frequency by 100. Genetic distance = \(0.22 \times 100 = 22\) cM The genetic distance between SNPs \(x\) and \(y\) is 22 centimorgans.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recombination Frequency
Understanding the recombination frequency is essential for genetic mapping and discovering how genes and genetic markers are inherited. It represents the likelihood of a crossover occurring between two genetic loci during meiosis, the process that leads to the production of gametes such as sperm or eggs. When two genetic markers, such as SNPs, are more frequently inherited separately rather than together, it indicates that they are more likely to be separated during recombination due to their physical distance on a chromosome.

In our exercise, we calculate the recombination frequency by taking the sum of the offspring that have recombinant genotypes (i.e., the genotypes that are different from the parent strains) and dividing this number by the total number of offspring. This frequency tells us how often recombination occurs between two points, in this case, SNPs, on a chromosome. The formula used is:
\( \text{Recombination frequency} = \frac{\text{Number of recombinant offspring}}{\text{Total number of offspring}} \).

It's important to make this concept relatable by considering it like a measure of how 'close' or 'far' two markers are on the DNA strand—closer markers recombine less frequently and thus have a lower recombination frequency.
Centimorgans
The unit centimorgan (cM) is named after the American geneticist Thomas Hunt Morgan, who made significant contributions to the field of genetics. It is used to measure genetic distance and one centimorgan is equivalent to a 1% chance that a marker at one genetic locus will be separated from a marker at another locus due to recombination in a single generation.

In the context of our exercise, to convert the calculated recombination frequency into centimorgans, we simply multiply the frequency by 100. Therefore, a recombination frequency of 0.22 corresponds to 22 cM, indicating that there is a 22% chance that the two SNPs will be separated during the formation of gametes. This measurement provides a more tangible representation of genetic distance.

When explaining centimorgans, it's helpful to visualize a chromosome as a roadmap, with centimorgans as the 'miles' measuring the distance between various 'locations' or genes. This can make the concept of genetic linkage and distance more approachable for students.
SNPs
Single Nucleotide Polymorphisms, commonly known as SNPs (pronounced 'snips'), are the most common type of genetic variation among individuals. A SNP represents a difference in a single nucleotide—A, T, C, or G—in the DNA sequence. For instance, a SNP may replace the nucleotide cytosine (C) with thymine (T) at a specific location in the genome. Although most SNPs do not have any observable effect on an individual’s health or physical characteristics, some can be very informative in linking certain traits or diseases with specific genetic variations.

In the given exercise, SNPs 'x' and 'y' are used as genetic markers to explore inheritance patterns in mice. The difference in the SNPs between strains A and B allow researchers to track which strain the offspring have inherited particular genetic material from. Understanding how frequently recombination occurs between these SNPs helps in mapping their position on the chromosome and can be vital for genetic research, such as determining the likelihood of inheriting a genetic disorder.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The genes dumpy\((d p),\) clot \((c l),\) and apterous \((a p)\) are linked on chromosome II of Drosophila. In a series of two-point mapping crosses, the following genetic distances were determined. What is the sequence of the three genes?

What possible conclusions can be drawn from the observations that in male Drosophila, no crossing over occurs, and that during meiosis, synaptonemal complexes are not seen in males but are observed in females where crossing over occurs?

Review the Chapter Concepts list on page \(138 .\) Most of these center around the process of crossing over between linked genes. Write a short essay that discusses how crossing over can be detected and how the resultant data provide the basis of chromosome mapping.

Why does more crossing over occur between two distantly linked genes than between two genes that are very close together on the same chromosome?

In Drosophila, a cross was made between females-all expressing the three \(X\) -linked recessive traits scute bristles \((s c),\) sable body \((s),\) and vermilion eyes \((v)-\) and wild-type males. In the \(\mathrm{F}_{1},\) all females were wild type, while all males expressed all three mutant traits. The cross was carried to the \(\mathrm{F}_{2}\) generation, and 1000 offspring were counted, with the results shown in the following table. No determination of sex was made in the data. (a) Using proper nomenclature, determine the genotypes of the \(P_{1}\) and \(F_{1}\) parents. (b) Determine the sequence of the three genes and the map distances between them. (c) Are there more or fewer double crossovers than expected? (d) Calculate the coefficient of coincidence. Does it represent positive or negative interference?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free