In Drosophila, a female fly is heterozygous for three mutations, Bar eyes \((B),\) miniature wings \((m),\) and ebony body \((e)\) Note that Bar is a dominant mutation. The fly is crossed to a male with normal eyes, miniature wings, and ebony body. The results of the cross are as follows. Interpret the results of this cross. If you conclude that linkage is involved between any of the genes, determine the map distance(s) between them.

Question: Determine if there is any linkage between the genes involved in the mutations and calculate the map distance(s) between the linked genes based on the cross between a female fly heterozygous for Bar eyes (B), miniature wings (m), and ebony body (e) and a male fly with normal eyes, miniature wings, and ebony body. Answer: To determine the presence of linkage and calculate map distance, perform the following steps: 1. Determine the genotypes of the parent flies (female: BbMmEe, male: bbmmee). 2. Identify the possible gametes produced by each parent fly. 3. Perform the cross between the two parent flies and note the resulting offspring genotypes. 4. Investigate the likelihood of linkage between the genes by comparing the observed offspring ratio to the expected 1:1:1:1 ratio for independent assortment. 5. Calculate the recombination frequency between the linked genes using the provided offspring data. 6. Use the recombination frequency to determine the map distance between the linked genes. 7. Interpret the results and draw conclusions on the presence of linkage and the map distance between the genes. Note that to perform steps 5 and 6, you will need the specific data on the offspring counts from the cross.