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Chapter 17: Problem 11

If you performeda PCR experimentstarting withonly onecopy of double-stranded DNA, approximately how many DNA molecules would be present in the reaction tube after 15 cycles of amplification?

Short Answer

Expert verified
Answer: 32,768 DNA molecules.

Step by step solution

01

Identify the number of cycles and initial DNA molecules

In this problem, we have 15 cycles of amplification (n=15) and initially, there is only 1 copy of double-stranded DNA (Initial number of DNA molecules = 1).
02

Use the amplification formula

To calculate the DNA molecules after the amplification, we use the formula: Number of DNA molecules after n cycles = 2^n * Initial number of DNA molecules
03

Calculate the number of DNA molecules after 15 cycles

Now, let's plug our values into the formula and compute the final number of DNA molecules present after 15 cycles: Number of DNA molecules after 15 cycles = 2^15 * 1 = 32768 So, there will be approximately 32,768 DNA molecules present in the reaction tube after 15 cycles of amplification.

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Most popular questions from this chapter

In a typical PCR reaction, describe what is happening in stages occurring at temperature ranges (a) \(92-95^{\circ} \mathrm{C},\) (b) \(45-65^{\circ} \mathrm{C},\) and (c) \(65-75^{\circ} \mathrm{C}\)

Why is genome editing by CRISPR-Cas advantageous over traditional methods for creating knockout or transgenic animals? Explain your answers.

What safety considerations must be taken before CRISPR-Cas is used to edit human embryos to cure disease?

The CRISPR-Cas system has great potential but also raises many ethical issues about its potential applications because theoretically it can be used to edit any gene in the genome. What do you think are some of the concerns about the use of CRISPR. Cas on humans? Should CRISPR-Cas applications be limited for use on only certain human genes but not others? Explain your answers.

Provide one example of a CRISPR-Cas application for biotechnology.
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