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Chapter 4: Problem 13

In cats, orange coat color is determined by the \(b\) allele, and black coat color is determined by the \(B\) allele. The heterozygous condition results in a coat pattern known as tortoiseshell, These genes are X-linked. What kinds of offspring would be expected from a cross of a black male and a tortoiseshell female? What are the chances of getting a tortoiseshell male?

Short Answer

Expert verified
Answer: The chances of getting a tortoiseshell male offspring from this cross are 0%.

Step by step solution

01

Identify the genotypes

The genotypes of the given cats are: - Black male: XY (with B allele on the X chromosome) - Tortoiseshell female: XX (with B allele on one X chromosome and b allele on the other X chromosome)
02

Construct a Punnett square

To find the expected offspring from the cross between the black male and the tortoiseshell female, create a Punnett square using the parents' genotypes: B b +-----------+-----------+ X | XB | Xb | +-----------+-----------+ Y | YB | Yb | +-----------+-----------+
03

Determine expected offspring

From the Punnett square, we can determine the possible genotypes and phenotypes of their offspring: - XB female (black): 50% probability - Xb female (tortoiseshell): 50% probability - YB male (black): 50% probability - Yb male (orange): 50% probability
04

Calculate the probability of a tortoiseshell male

From the possible offspring genotypes, there are no tortoiseshell males (XY with both B and b alleles). So, the chances of getting a tortoiseshell male are 0%.

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Most popular questions from this chapter

The following genotypes of two independently assorting autosomal genes determine coat color in rats: \(A-B-(\text { gray }) ; A-b b\) (yellow) \(; a a B-\) (black); \(a a b b\) (cream) A third gene pair on a separate autosome determines whether any color will be produced. The \(C C\) and \(C c\) genotypes allow color according to the expression of the \(A\) and \(B\) alleles. However, the ce genotype results in allbino rats regardless of the \(A\) and \(B\) alleles present. Determine the \(F_{1}\) phenotypic ratio of the following crosses: (a)AAbbCC \(\times\) aaBBcc; (b) \(A a B B c c \times A A B b c c\) (c) \(A a B b C c \times A a B b c c\)

In cattle, coats may be solid white, solid black, or black-and-white spotted. When true-breeding solid whites are mated with truebreeding solid blacks, the \(\mathrm{F}_{1}\) generation consists of all solid white individuals. After many \(\mathrm{F}_{1} \times \mathrm{F}_{1}\) matings, the following ratio was observed in the \(\mathrm{F}_{2}\) generation: \(12 / 16\) solid white \(3 / 16\) black-and-white spotted \(1 / 16\) solid black Explain the mode of inheritance governing coat color by determining how many gene pairs are involved and which genotypes yield which phenotypes. Is it possible to isolate a true-breeding strain of black-and-white spotted cattle? If so, what genotype would they have? If not, explain why not.

In four o'clock plants, many flower colors are observed. In a cross involving two true-breeding strains, one crimson and the other white, all of the \(P_{1}\) generation were rose color. In the \(F_{2}\), four new phenotypes appeared along with the \(P_{1}\) and \(F_{1}\) parental colors. The following ratio was obtaincd: \(1 / 16\) erimson \(2 / 16\) orange \(1 / 16\) yellow \(2 / 16\) magenta \(4 / 16\) rose \(2 / 16\) pale yellow \(4 / 16\) white Propose an explanation for the inheritance of these flower colors.

Three gene pairs located on separate autosomes determine flower color and shape as well as plant height. The first pair exhibits incomplete dominance, where color can be red, pink (the heterozygote), or white. The second pair leads to the dominant personate or recessive peloric flower shape, while the third gene pair produces either the dominant tall trait or the recessive dwarf trait. Homozygous plants that are red, personate, and tall are crossed with those that are white, peloric, and dwarf. Determine the \(F_{1}\) genotype(s) and phenotype(s). If the \(F_{1}\) plants are inter. bred, what proportion of the offspring will exhibit the same phenotype as the \(\mathrm{P}_{1}\) plants?

In Dexter and Kerry cattle, animals may be polled (hornless) or horned. The Dexter animals have short legs, whereas the Kerry animals have long legs. When many offspring were obtained from matings between polled Kerrys and horned Dexters, half were found to be polled Dexters and half polled Kerrys. When these two types of \(\mathrm{F}_{1}\) cattle were mated to one another, the following \(\mathrm{F}_{2}\) data were obtained: \(3 / 8\) polled Dexters 3/8 polled Kerrys \(1 / 8\) horned Dexters \(1 / 8\) horned Kerrys A geneticist was puzzled by these data and interviewed farmers who had bred these cattle for decades. She learned that Kerrys were true-breeding. Dexters, on the other hand, were not truebreeding and never produced as many offspring as Kerrys. Provide a genetic explanation for these observations.
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