A plant breeder observed that for a certain leaf trait of maize that shows two phenotypes (phenotype 1 and phenotype 2), the \(\mathrm{F}_{1}\) generation exhibits 200 plants with phenotype 1 and 160 with phenotype 2. Using two different null hypotheses and chi-square analysis, compute if the data fits (a) a 3: 1 ratio, and (b) a 1: 1 ratio.

Short Answer

Expert verified
Explain your answer. Answer: The data better fits the 1:1 ratio, though the fit is not strict. The calculated chi-square value of 4.44 is slightly greater than the critical chi-square value of 3.84, indicating a stronger support for the 1:1 ratio even though it does not strictly fit the data. Meanwhile, the data does not fit the 3:1 ratio, since the calculated chi-square value (72.59) is far greater than the critical chi-square value (3.84).

Step by step solution

01

Collect given data

We have 200 plants with phenotype 1 and 160 plants with phenotype 2 in the \(\mathrm{F}_{1}\) generation. We will first perform a chi-square analysis for a 3:1 ratio and then for a 1:1 ratio.
02

Calculate the expected numbers for the 3:1 ratio hypothesis

A 3:1 ratio means that there will be 3 times more plants with phenotype 1 than with phenotype 2. To calculate the expected number of plants in each phenotype, we can first calculate the total number of plants and divide that by the ratio denominator (3+1) = 4, and then multiply each ratio part by the quotient. Total number of plants = 200 + 160 = 360 For phenotype 1 (3 parts of ratio): Expected number = (360 / 4) * 3 = 270 For phenotype 2 (1 part of ratio): Expected number = (360 / 4) * 1 = 90
03

Perform Chi-square test for the 3:1 ratio hypothesis

The chi-square formula is: \(\chi^2 = \sum\frac{(O-E)^2}{E}\), where \(O\) is the observed value and \(E\) is the expected value. For phenotype 1: \(\chi^2_1 = \frac{(200-270)^2}{270} = \frac{(-70)^2}{270} = \frac{4900}{270} = 18.15\) For phenotype 2: \(\chi^2_2 = \frac{(160-90)^2}{90} = \frac{70^2}{90} = \frac{4900}{90} = 54.44\) Total chi-square value: \(\chi^2 = 18.15 + 54.44 = 72.59\)
04

Calculate the expected numbers for the 1:1 ratio hypothesis

Now, let's test if the plant population fits a 1:1 ratio. Each phenotype will have half the total number of plants. Total number of plants = 360 For phenotype 1 (1 part of ratio): Expected number = (360 / 2) = 180 For phenotype 2 (1 part of ratio): Expected number = (360 / 2) = 180
05

Perform Chi-square test for the 1:1 ratio hypothesis

We will use the same chi-square formula from step 3 for the 1:1 ratio hypothesis. For phenotype 1: \(\chi^2_1 = \frac{(200-180)^2}{180} = \frac{20^2}{180} = \frac{400}{180} = 2.22\) For phenotype 2: \(\chi^2_2 = \frac{(160-180)^2}{180} = \frac{(-20)^2}{180} = \frac{400}{180} = 2.22\) Total chi-square value: \(\chi^2 = 2.22 + 2.22 = 4.44\)
06

Determine if data fits any of the ratios based on chi-square values

We have performed chi-square tests for both the 3:1 and 1:1 ratio hypotheses and obtained chi-square values of 72.59 and 4.44, respectively. To determine if the data fits either of these ratios, we will look for the critical chi-square value for a 5% level of significance and 1 degree of freedom (since there are 2 phenotypes). We find that the critical chi-square value is 3.84. Comparing the calculated chi-square values to the critical chi-square: - For the 3:1 ratio, the calculated chi-square (72.59) is far greater than the critical chi-square (3.84), suggesting that the observed data does not fit the 3:1 ratio. - For the 1:1 ratio, the calculated chi-square (4.44) is slightly greater than the critical chi-square (3.84), suggesting that the observed data does not strictly fit the 1:1 ratio either. However, the difference is minor, and it is relatively closer to the 1:1 ratio than the 3:1 ratio. In conclusion, the data does not fit the 3:1 ratio but provides stronger support for the 1:1 ratio even though the difference between calculated and critical chi-squares is minimal.

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Most popular questions from this chapter

Two true-breeding pea plants are crossed. One parent is round, terminal, violet, constricted, while the other expresses the contrasting phenotypes of wrinkled, axial, white, full. The four pairs of contrasting traits are controlled by four genes, each located on a separate chromosome. In the \(F_{1}\) generation, only round, axial, violet, and full are expressed. In the \(\mathrm{F}_{2}\) generation, all possible combinations of these traits are expressed in ratios consistent with Mendelian inheritance. (a) What conclusion can you draw about the inheritance of these traits based on the \(\mathrm{F}_{1}\) results? (b) Which phenotype appears most frequently in the \(\mathrm{F}_{2}\) results? Write a mathematical expression that predicts the frequency of occurrence of this phenotype. (c) Which \(\mathrm{F}_{2}\) phenotype is expected to occur least frequently? Write a mathematical expression that predicts this frequency. (d) How often is either \(P_{1}\) phenotype likely to occur in the \(F_{2}\) generation? (e) If the \(F_{1}\) plant is testcrossed, how many different phenotypes will be produced?

Consider three independently assorting gene pairs, \(A / a, B / b,\) and \(C / c,\) where each demonstrates typical dominance \((A-, B-, C-)\) and recessiveness \((a a, b b, c c) .\) What is the probability of obtaining an offspring that is \(A A B b C c\) from parents that are \(A a B b C C\) and \(A A B b C c ?\)

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