Chapter 14: Q 28P (page 476)

Question: If intracellular $[ATP] = 5mM, [ADP] = 0.5mM$ , and $[P_{i}] =$ $1.0mM$ , calculate the concentration of AMP at pH 7 and $25^{°} C$ under the condition that the adenylate kinase reaction is at equilibrium.

Short Answer

Expert verified

Answer

The concentration of AMP is 0.23 mM.

Step by step solution

Step-by-step-solutionStep 1: Calculating equilibrium constant

To calculate equilibrium constant $(K)$ for the reaction of $2ADP \to ATP + AMP$ at its equilibrium using the following equation, where c marks concentrations:

In this case, K is determined using the following formula $:K = \frac{c(ATP)c(AMP)}{{c(ADP)}^{2}}$

Combining the given equations

To compute the concentration of AMP, we'll combine the previous and subsequent reactions of the step two into one:

In this equation stands for standard Gibbs free energy, represents gas constant and T is temperature.

Calculating the concentration

After combining those two equations we calculate the concentration of AMP at pH 7 and 25°C (298K) under the condition that the adenylate kinase reaction is at equilibrium,

$\frac{c(ATP)c(AMP)}{a {(A D P)}^{2}} = e^{\frac{- ∆ σ}{B T}}$

$c(AMP) = 0.23mM$

Hence, the concentration of AMP is 23mM.

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Question: If intracellular $[ATP] = 5mM, [ADP] = 0.5mM$ , and $[P_{i}] =$ $1.0mM$ , calculate the concentration of AMP at pH 7 and $25^{°} C$ under the condition that the adenylate kinase reaction is at equilibrium.

Short Answer

Step by step solution

Step-by-step-solutionStep 1: Calculating equilibrium constant

Combining the given equations

Calculating the concentration

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Biology Textbooks

Ecosystems

Cells

Bioenergetics

Organ Systems

Control of Gene Expression

Energy Transfers

Study anywhere. Anytime. Across all devices.

Question: If intracellular [ATP] = 5mM, [ADP] = 0.5mM, and Pi=1.0mM , calculate the concentration of AMP at pH 7 and 25°Cunder the condition that the adenylate kinase reaction is at equilibrium.

Short Answer

Step by step solution

Step-by-step-solutionStep 1: Calculating equilibrium constant

Combining the given equations

Calculating the concentration

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Biology Textbooks

Ecosystems

Cells

Bioenergetics

Organ Systems

Control of Gene Expression

Energy Transfers

Study anywhere. Anytime. Across all devices.

Question: If intracellular $[ATP] = 5mM, [ADP] = 0.5mM$ , and $[P_{i}] =$ $1.0mM$ , calculate the concentration of AMP at pH 7 and $25^{°} C$ under the condition that the adenylate kinase reaction is at equilibrium.