Electrospray ionization mass spectrometry (ESI-MS) of proteins involves creating positively charged ions of the protein and separating them according to their mass-to-charge ratio (m/z).

(a) What causes the different positive charges on different particles of the protein?

(b) The amino acid composition (in numbers of residues per chain) of hen egg-white lysozyme (HEWL) is as follows:

P 2 Y 3 N 14 H 1

D 7 M 2 L 8 E 2

C 8 R 11 G 12 F 3

A 12 I 6 K 6 V 6

S 10 W 6 T 7 Q 3

What is the maximum positive charge that can be present on a HEWL ion?

Short Answer

Expert verified
  1. The positive charges are due to the protonation of basic side chains of histidine, lysine, and arginine due to the N-terminal amine group of the protein.
  2. The maximum positive charge which can be present on HEWL ion is 19.

Step by step solution

01

Electrospray Ionization – Mass Spectrometry (ESI - MS)

Mass Spectroscopy is the technique used for characterising and sequencing proteins. For ions in the gas phase, mass spectrometry precisely detects the mass-to-charge (m/z) ratio (where m is the ion's mass and z is its charge).In Electrospray Ionization – Mass Spectrometry (ESI - MS), a solution of a macromolecule like a peptide is sprayed from a tiny capillary tube maintained at high voltage (4,000 V), generating fine, highly charged droplets from which the solvent quickly evaporates. This produces a sequence of macromolecular ions in the gas phase with ionic charges ranging from +0.5 to +2 per kilodalton.

02

Explanation

The positive charges on different particles during ESI - MS is because of the protonation of basic side chains of amino acids i.e., Histidine, arginine, and lysine. The positive charge is also because of the protonation of N-terminal amine group of the protein chain.

The HEWL ion contains one histidine, 6 lysine, and 11 arginine residues. Also, the N-terminus contains one NH2, so the maximum positive charge which can be present on it is 19.

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Most popular questions from this chapter

You wish to sequence the light chain of a protease inhibitor from the Brassica nigra plant. Cleavage of the light chain by trypsin and chymotrypsin yields the following fragments. What is the sequence of the light chain?

Chymotrypsin

1. Leu–His–Lys–Gln–Ala–Asn–Gln–Ser–Gly–Gly–Gly–Pro–Ser

2. Gln–Gln–Ala–Gln–His–Leu–Arg–Ala–Cys–Gln–Gln–Trp

3. Arg–Ile–Pro–Lys–Cys–Arg–Lys–Phe

Trypsin

4. Arg

5. Ala–Cys–Gln–Gln–Trp–Leu–His–Lys

6. Cys–Arg

7. Gln–Ala–Asn–Gln–Ser–Gly–Gly–Gly–Pro–Ser

8. Phe–Gln–Gln–Ala–Gln–His–Leu–Arg

9. Ile–Pro–Lys

10. Lys

What fractionation procedure could be used to purify protein 1 from a mixture of three proteins whose amino acid compositions are as follows?

1. 25% Ala, 20% Gly, 20% Ser, 10% Ile, 10% Val, 5% Asn, 5% Gln, 5% Pro

2. 30% Gln, 25% Glu, 20% Lys, 15% Ser, 10% Cys

3. 25% Asn, 20% Gly, 20% Asp, 20% Ser, 10% Lys, 5% Tyr

All three proteins are similar in size and pI, and there is no antibody available for protein 1.

You wish to determine the sequence of a polypeptide that has the following amino acid composition.

1 Ala 4 Arg 2 Asn 3 Asp 4 Cys 3 Gly 1 Gln 4 Glu 1 His 1 Lys 1 Met 1 Phe 2 Pro 4 Ser 2 Tyr 1 Trp

(a) What is the maximum number of peptides you can expect if you cleave the polypeptide with cyanogen bromide?

(b) What is the maximum number of peptides you can expect if you cleave the polypeptide with chymotrypsin?

(c) Analysis of the intact polypeptide reveals that there are no free sulfhydryl groups. How many disulfide bonds are likely to be present?

(d) How many different arrangements of disulfide bonds are possible?

Explain how an antibody could be useful for purifying a protein and for determining its concentration.

Identify the first residue obtained by Edman degradation of cytochrome c from (a) Drosophila, (b) baker’s yeast, and (c) wheat germ (see Table 5-6).

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