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Chapter 20: Problem 23

What is the chance that a dihybrid cross will produce a homozygous recessive in both traits? a. \(9 / 16\) b. \(1 / 4\) c. \(1 / 16\) d. \(3 / 16\) e. \(1 / 8\)

Short Answer

Expert verified
The chance that a dihybrid cross will produce a homozygous recessive in both traits is c. \(1 / 16\).

Step by step solution

01

Determine the parental genotypes for each trait

In a dihybrid cross, the parents are both heterozygous for both traits. So, for our example, let Trait 1 be represented by "A" (dominant) and "a" (recessive) and Trait 2 be represented by "B" (dominant) and "b" (recessive). The parental genotypes will be AaBb x AaBb.
02

Create Punnett squares for each trait

We will create a Punnett square for each trait to determine the probability of getting a homozygous recessive genotype for each. Trait 1: | | A | a | |---|---|---| | A | AA| Aa| | a | Aa| aa| Trait 2: | | B | b | |---|---|---| | B | BB| Bb| | b | Bb| bb| From the Punnett squares, we find the probability of getting a homozygous recessive genotype for Trait 1 (aa) is 1/4 and for Trait 2 (bb) is also 1/4.
03

Calculate the combined probability

To find the combined probability of getting a homozygous recessive genotype for both traits (aabb), we multiply the probabilities of the individual traits: Probability (Trait 1) x Probability (Trait 2) = \(\frac{1}{4}\) x \(\frac{1}{4}\)= \(\frac{1}{16}\) Therefore, the chance that a dihybrid cross will produce a homozygous recessive in both traits is 1/16. The correct answer is c. \(1 / 16\).

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Most popular questions from this chapter

Which of the following is not a feature of multifactorial inheritance? a. Effects of dominant alleles are additive. b. Genes affecting the trait may be on multiple chromosomes c. Environment influences phenotype. d. Recessive alleles are harmful.

Assume two normal parents have a color-blind son. Which parent is responsible for color blindness in the son? a. the mother b. the father c. either parent d. Neither parent-two normal parents cannot have a color- blind son.

Which of these is a correct statement? a. Each gamete contains two alleles for each trait. b. Each individual has one allele for each trait c. Fertilization gives each new individual one allele for each trait d. All of these are correct. e. None of these is correct.

Two wavy-haired individuals (neither curly hair nor straight hair are completely dominant) reproduce. What are the chances that their children will have wavy hair? a. \(0 \%\) b. \(25 \%\) c. \(50 \%\) d. \(100 \%\)

How is an X-linked trait different from an autosomal trait? (page \(481)\)
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