You are the vice president of finance for exploratory resources, headquartered in Houston, Texas. In January 20X1, your firm’s Canadian subsidiary obtained a six-month loan of 150,000 Canadian dollars from a bank in Houston to finance the acquisition of a titanium mine in Quebec province. The loan will also be repaid in Canadian dollars. At the time of the loan, the spot exchange rate was U.S. \(0.8995/ Canadian dollars and the Canadian currency was selling at a discount in the forward market. The June 20X1 contract (face value = C\)150,000 per contract) was quoted at U.S. $0.8930/ Canadian dollar.

a. Explain how the Houston bank could lose on this transaction assuming no hedging.

b. If the bank does hedge with the forward contract, what is the maximum amount it can lose?

Short Answer

Expert verified

a.The Houston bank lose on this transaction as the value of the Canadian dollar declined relative to the U.S. dollar. If the bank remained unhedged it would have lost $975.

b.If the bank does hedge with the forward contract, the maximum amount it can lose is $975.

Step by step solution

01

Spot Market

When exchange rate was U.S. $0.8995/ Canadian dollar, the original loan value equals

Loanvalue=Canadiandollarvalue×U.SdollarperCanadiandollar=150,000×$0.8995=$134,925

02

Forward market

When exchange rate was U.S. $0.8930/ Canadian dollar, the repayment value of loan equals

Repaymentvalue=Canadiandollarvalue×U.SdollarperCanadiandollar=150,000×$0.8930=$133,950

Hence, buying value is greater than the selling value. It is a loss.

03

Calculation of loss

Loss=LoanvalueRepaymentvalue=$134,925$133,950=$975

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  1. If there is a 10 percent gain in the value of the dollar versus the Peruvian nuevo sol, what will be the total percentage return to the Peruvian investor? First, determine the new dollar value of the investment and multiply this figure by 1.10. Divide this answer by \)7,500 and get a percentage value, and then subtract 100 percent to get the percentage return.
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Spot .................................................... \)0.8202

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