Rate of a reaction: \(\mathrm{A}+2 \mathrm{~B} \rightarrow \mathrm{P}\) is \(2 \times 10^{-2} \mathrm{M} / \mathrm{min}\), when concentrations of each \(A\) and \(B\) are \(1.0 \mathrm{M}\). If the rate of reaction, \(r=K[\mathrm{~A}]^{2}[\mathrm{~B}]\), the rate of reaction when half of the \(\mathrm{B}\) has reacted should be (a) \(5.625 \times 10^{-3} \mathrm{M} / \mathrm{min}\) (b) \(3.75 \times 10^{-3} \mathrm{M} / \mathrm{min}\) (c) \(9.375 \mathrm{M} / \mathrm{min}\) (d) \(2.5 \times 10^{-3} \mathrm{M} / \mathrm{min}\)

Short Answer

Expert verified
The rate of reaction when half of B has reacted is (b) 3.75 x 10^-3 M/min.

Step by step solution

01

Determine the Rate Law and Rate Constant

Given the rate of reaction, r, when the concentrations of A and B are both at 1.0 M, we can calculate the rate constant, K. The rate law is given by r = K[A]^2[B]. We plug in r = 2x10^-2 M/min, [A] = 1.0 M, and [B] = 1.0 M to solve for K.
02

Calculate the Rate Constant, K

Substitute the given values into the rate law: 2x10^-2 M/min = K * (1.0 M)^2 * (1.0 M). Simplify the equation to find the value of K.
03

Determine the New Rate of Reaction

When half of B has reacted, [B] becomes 0.5 M (since it starts at 1.0 M). Since the concentration of A does not change, it remains 1.0 M. Use the calculated K to find the new rate r when [A] = 1.0 M and [B] = 0.5 M using the rate law.
04

Solve for the New Rate of Reaction, r

Substitute the known values into the rate law with the concentration of B halved: r = K[A]^2[B]. Use [A] = 1.0 M, [B] = 0.5 M and the previously found value of K to find the new rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
Understanding the rate law of a chemical reaction unlocks the relationship between reactant concentrations and the rate at which products form. The rate law is an equation that mathematically describes this relationship. Specifically, it indicates how the rate depends on the concentration of each reactant. For instance, in the provided exercise, the rate law is expressed as r = K[A]^2[B], where r represents the rate, K is the rate constant, and the exponents of [A] and [B] signify their respective effects on the rate.

In this scenario, the rate is directly proportional to the square of the concentration of A and the first power of B. These exponents are known as reaction orders and play a critical role in the kinetics of the reaction. When working with rate laws, a step-by-step approach involves first identifying the rate law from experimental data, then using known concentrations to solve for the rate constant.
Rate Constant
The rate constant, often denoted as K, is a proportionality factor that directly impacts the rate of a chemical reaction. It is a unique value for every chemical reaction at a given temperature. In simple terms, it quantifies the rate at which reactants transform into products.

To calculate the rate constant from the rate law, one must know the rate of the reaction and the concentrations of the reactants under specific conditions, as seen in step 2 of the provided solution. After obtaining the rate constant, it can be used to predict the rate of the reaction under different concentrations of reactants. This is vital as it remains constant at a constant temperature and provides insights into the reactivity and mechanism of the reaction.
Reactant Concentration
Reactant concentration, represented by [A], [B], etc., is a measure of the amount of a reactant within a given volume. In chemical kinetics, it's crucial to understand how changes in reactant concentrations influence the reaction rate. As exemplified in the exercise, if the concentration of B is reduced by half, from 1.0 M to 0.5 M, the rate of the reaction will also change.

This is because the rate law equation includes the concentrations raised to their respective reaction orders. When a reactant concentration changes, the rate can be recalculated by substituting the new concentration value into the rate law, while keeping the rate constant, K, the same (unless the temperature changes). The concentration of reactants typically decreases over time as they form products, and monitoring these changes can help control the reaction rate for desired outcomes.
Chemical Kinetics
Chemical kinetics is a branch of physical chemistry that deals with the speed or rate at which chemical reactions occur. It examines the factors that influence rates of reactions and establishes the mechanisms by which reactions proceed. Some of these factors include reactant concentrations, temperature, and the presence of catalysts.

The study of kinetics is fundamental in predicting how long a reaction will take and how it can be optimized for industrial or laboratory settings. Understanding kinetics can help in the design of chemical reactors and in the safe storage and handling of reactive materials. It's pivotal for students to grasp the concepts of chemical kinetics as they can then apply these principles to various situations, including the exercise given, which focuses on manipulating reactant concentrations to determine a reaction's rate.

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Most popular questions from this chapter

Two substances, 'A' and 'B' are initially present as \(\left[A_{0}\right]=8\left[B_{0}\right]\) and \(t_{1 / 2}\) for the firstorder decomposition of 'A' and 'B' are 10 and \(20 \mathrm{~min}\), respectively. If they start decomposing at the same time, after how much time, the concentration of both of them would be same? (a) \(20 \mathrm{~min}\) (b) \(40 \mathrm{~min}\) (c) \(60 \mathrm{~min}\) (d) \(200 \mathrm{~min}\)

The rate equation for an autocatalytic reaction \(\mathrm{A}+\mathrm{R} \stackrel{k}{\longrightarrow} \mathrm{R}+\mathrm{R}\) is \(r_{\mathrm{A}}=-\frac{\mathrm{d} C_{\mathrm{A}}}{\mathrm{d} t}=k C_{\mathrm{A}} C_{\mathrm{R}}\) The rate of disappearance of reactant \(\mathrm{A}\) is maximum when (a) \(C_{\mathrm{A}}=2 C_{\mathrm{R}}\) (b) \(C_{\mathrm{A}}=C_{\mathrm{R}}\) (c) \(C_{\mathrm{A}}=C_{\mathrm{R}} / 2\) (d) \(C_{\mathrm{A}}=\left(C_{\mathrm{R}}\right)^{1 / 2}\)

The rate constant is given by the equation: \(K=P \cdot A \cdot e^{-E_{a} / R T}\). Which factor should register a decrease for the reaction to proceed more rapidly? (a) \(T\) (b) \(A\) (c) \(E_{\text {a }}\) (d) \(P\)

A kinetic study of the reaction: \(\mathrm{A} \rightarrow\) products provides the data: \(t=0 \mathrm{~s},[\mathrm{~A}]=2.00 \mathrm{M} ;\) \(\begin{array}{llll}500 \mathrm{~s}, & 1.00 \mathrm{M} ; 1500 \mathrm{~s}, 0.50 \mathrm{M} ; 3500 \mathrm{~s}\end{array}\) \(0.25 \mathrm{M}\). In the simplest possible way determine, whether this reaction is of (a) zero order (b) first order (c) second order (d) third order

In a first-order reaction, the activity of reactant drops from \(800 \mathrm{~mol} / \mathrm{dm}^{3}\) to \(50 \mathrm{~mol} / \mathrm{dm}^{3}\) in \(2 \times 10^{4} \mathrm{~s}\). The rate constant of the reaction, in \(\mathrm{s}^{-1}\), is (a) \(1.386 \times 10^{-4}\) (b) \(1.386 \times 10^{-3}\) (c) \(1.386 \times 10^{-5}\) (d) \(5.0 \times 10^{3}\)

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