For the reaction: \(\mathrm{A}_{2}(\mathrm{~g}) \rightarrow \mathrm{B}(\mathrm{g})+\frac{1}{2} \mathrm{C}(\mathrm{g})\) pressure of the system increases from 100 to \(120 \mathrm{~mm}\) in 5 min. The average rate of disappearance of \(\mathrm{A}_{2}\) (in \(\mathrm{mm} / \mathrm{min}\) ) in this time interval is (a) 4 (b) 8 (c) 2 (d) 16

Short Answer

Expert verified
The average rate of disappearance of A2 is 4 mm/min.

Step by step solution

01

Understand the concept of reaction rate

The average rate of a chemical reaction over a given time interval is defined as the change in concentration of a reactant or product per unit time. For disappearance of a reactant, it is calculated using the formula: Average rate = - (Change in concentration of A2) / (Change in time). The negative sign indicates that the concentration of the reactant is decreasing.
02

Calculate the change in concentration

The change in concentration of A2 is given by the change in pressure since it is a gaseous reactant, and pressure is directly proportional to concentration. Change in pressure = Final pressure - Initial pressure = 120 mm - 100 mm = 20 mm. This change in pressure occurred over a period of 5 minutes.
03

Calculate the average rate of disappearance of A2

The average rate of disappearance of A2 is then calculated by dividing the change in pressure by the change in time. Average rate = - (Change in pressure) / (Change in time) = - (20 mm) / (5 min) = -4 mm/min. The negative sign is conventional for the rate of disappearance of reactants.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Kinetics
Understanding reaction kinetics is essential when studying how reactions occur and at what rates they progress. Reaction kinetics, often simply called kinetics, looks into the factors that affect the speed of a chemical reaction and establishes the relationship between the reactivity of molecules and the rate at which a reaction proceeds.

Some of the main aspects of kinetics encompass the energy needed for reactions to occur, known as the activation energy, the orientation of reactant molecules when they collide, and the frequency of collisions. Factors like temperature, pressure, concentration of reactants, and the presence of catalysts are pivotal as they influence these aspects and thereby manipulate how fast a reaction can go from starting reactants to final products. A fundamental understanding of kinetics not only aids in predicting reaction rates but also in controlling processes in industries like pharmaceuticals and biochemical engineering.
Average Rate of Reaction
When we talk about the average rate of reaction, we're measuring how quickly reactants turn into products over a period of time. It's an indicator of the speed of a chemical reaction. Remember, for the disappearance of a reactant, we often use a negative sign because the quantity of reactant is diminishing.

By following the formula Average rate = - (Change in concentration of A2) / (Change in time), it becomes clearer that if the concentration of a reactant decreases rapidly, the reaction rate is high. Conversely, very gradual declines in reactant concentration indicate a slower reaction. This concept is instrumental in the field of chemistry, as it helps predict the time needed for a reaction to reach completion, which is crucial for planning and optimizing chemical production.
Pressure and Concentration Relationship
In the context of gases, pressure plays a significant role and is directly related to the concentration of gas molecules. According to the ideal gas law, pressure is directly proportional to the number of molecules in a given volume at a constant temperature. This implies that an increase in pressure results from an increase in the number of gas molecules - suggesting a higher concentration.

As pressure changes, it can affect the rate of a reaction by altering the concentration of the gaseous reactant or product involved. More molecules in the same volume mean that they are more likely to collide with energy greater than the activation energy, a requirement for successful reactions. Understanding this relationship is vital when controlling reaction conditions, particularly in reactions involving gases where pressure can be a more convenient measure of concentration than molarity, especially on an industrial scale.

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Most popular questions from this chapter

In \(80 \%\) ethanol at \(55^{\circ} \mathrm{C}\), isopropyl bromide reacts with hydroxide ion according to the following kinetics: $$ \begin{array}{l} -\frac{\mathrm{d}[\mathrm{RX}]}{\mathrm{d} t}=\left(4.8 \times 10^{-5} \mathrm{M}^{-1} \mathrm{~s}^{-1}\right) \\ {[\mathrm{RX}]\left[\mathrm{OH}^{-}\right]+2.4 \times 10^{-6} \mathrm{~s}^{-1}[\mathrm{RX}]} \end{array} $$ What percentage of isopropyl bromide reacts by the \(S_{\mathrm{N}_{2}}\) mechanism when \(\left[\mathrm{OH}^{-}\right]=0.01 \mathrm{M} ?\) (a) \(16.67 \%\) (b) \(83.33 \%\) (c) \(66.67 \%\) (d) \(33.33 \%\)

For a first-order reaction: \(\mathrm{A} \rightarrow\) Product, the initial concentration of \(\mathrm{A}\) is \(0.1 \mathrm{M}\) and after time \(40 \mathrm{~min}\), it becomes \(0.025 \mathrm{M}\). What is the rate of reaction at reactant concentration \(0.01 \mathrm{M} ?\) (a) \(3.465 \times 10^{-4} \mathrm{~mol} \mathrm{lit}^{-1} \mathrm{~min}^{-1}\) (b) \(3.465 \times 10^{-5} \mathrm{~mol} \mathrm{lit}^{-1} \mathrm{~min}^{-1}\) (c) \(6.93 \times 10^{-4} \mathrm{~mol} \mathrm{lit}^{-1} \mathrm{~min}^{-1}\) (d) \(1.7325 \times 10^{-4} \mathrm{~mol} \mathrm{lit}^{-1} \mathrm{~min}^{-1}\)

When the concentration of 'A' is 0.1 M, it decomposes to give ' \(\mathrm{X}\) ' by a firstorder process with a rate constant of \(6.93 \times 10^{-2} \mathrm{~min}^{-1}\). The reactant 'A', in the presence of catalyst, gives ' \(\mathrm{Y}\) ' by a secondorder mechanism with the rate constant of \(0.2 \mathrm{~min}^{-1} \mathrm{M}^{-1} .\) In order to make half-life of both the processes, same, one should start the second-order reaction with an initial concentration of 'A' equal to (a) \(0.01 \mathrm{M}\) (b) \(2.0 \mathrm{M}\) (c) \(1.0 \mathrm{M}\) (d) \(0.5 \mathrm{M}\)

A substance 'A' decomposes in solution following first-order kinetics. Flask 1 contains 11 of \(1 \mathrm{M}\) solution of \(\mathrm{A}^{\prime}\) and flask 2 contains \(100 \mathrm{ml}\) of \(0.6 \mathrm{M}\) solution of 'A'. After \(8.0 \mathrm{~h}\), the concentration of 'A' in flask 1 becomes \(0.25 \mathrm{M}\). In what time, the concentration of 'A' in flask 2 becomes \(0.3 \mathrm{M}\) ? (a) \(8.0 \mathrm{~h}\) (b) \(3.2 \mathrm{~h}\) (c) \(4.0 \mathrm{~h}\) (d) \(9.6 \mathrm{~h}\)

The rate constant is given by the equation: \(K=P \cdot A \cdot e^{-E_{a} / R T}\). Which factor should register a decrease for the reaction to proceed more rapidly? (a) \(T\) (b) \(A\) (c) \(E_{\text {a }}\) (d) \(P\)

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