When dilute aqueous solution of \(\mathrm{AgNO}_{3}\) (excess) is added to KI solution, positively charged sol particles of \(\mathrm{AgI}\) are formed due to adsorption of ion (a) \(\mathrm{K}^{+}\) (b) \(\mathrm{Ag}^{+}\) (c) I (d) \(\mathrm{NO}_{3}\)

Short Answer

Expert verified
The positively charged sol particles of \(\mathrm{AgI}\) are formed due to adsorption of ion (b) \(\mathrm{Ag}^{+}\).

Step by step solution

01

Understand the concept of adsorption in colloids

Adsorption refers to the process where ions or molecules from a solution adhere to the surface of a solid, forming a thin film. In colloids, when two solutions are mixed, the excess ions in the solution tend to adsorb on the newly formed particles' surface, giving them a particular charge.
02

Identify the precipitate

When aqueous solutions of \(\mathrm{AgNO}_{3}\) and KI are mixed, a reaction occurs forming a precipitate of silver iodide \(\mathrm{AgI}\), as seen in the equation: \(\mathrm{AgNO}_{3} + \mathrm{KI} \rightarrow \mathrm{AgI}_{(s)} + \mathrm{KNO}_{3}\). The \(\mathrm{AgI}\) formed is a colloid.
03

Determine the excess ion in the solution

The problem states that \(\mathrm{AgNO}_{3}\) is in excess. After \(\mathrm{AgI}\) precipitates out, there will be an excess of \(\mathrm{Ag}^{+}\) ions in the solution.
04

Identify the adsorbed ion

The excess \(\mathrm{Ag}^{+}\) ions will be available to adsorb onto the surface of the \(\mathrm{AgI}\) particles. Because it is positively charged, the \(\mathrm{Ag}^{+}\) ion will give a positive charge to the colloidal particles.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Colloidal Particles
The term 'colloidal particles' refers to the tiny particles that exist in a colloidal system, which is the intermediate between a true solution and a suspension. These particles range in size from 1 to 1000 nanometers and are large enough to scatter light (an effect known as the Tyndall effect) yet too small to settle under the influence of gravity.

In the context of the textbook exercise, when a precipitation reaction occurs between \textsf{AgNO}\(_3\) and KI, colloidal particles of silver iodide (\textsf{AgI}) are formed. These particles arise because the product of the reaction is insoluble in water and forms a colloid. This colloidal system is unique as the particles acquire a charge during the formation process. The charging of colloidal particles can occur through adsorption, where ions from the surrounding solution attach to their surface. This process is crucial as it stabilizes the colloid by preventing the particles from clumping together, which would otherwise lead to the particles settling out as a precipitate.
Precipitation Reaction
A precipitation reaction is a chemical reaction that occurs in aqueous solutions when two ionic compounds are combined and produce a precipitate, an insoluble solid product that separates from the solution. Typically, these reactions follow the pattern of double displacement, where cations and anions swap partners.

In this reaction, \textsf{AgNO}\(_3\) and KI are mixed to form \textsf{AgI} as the insoluble solid precipitate and \textsf{KNO}\(_3\) as the soluble salt, as depicted by the equation: \textsf{AgNO}\(_3\) + KI → \textsf{AgI}\(_{(s)}\) + \textsf{KNO}\(_3\). The solid silver iodide that forms is then responsible for the establishment of a colloidal state, as it does not dissolve but remains dispersed throughout the solution. It is also during this reaction that adsorption occurs, leading to the charging of newly formed colloidal silver iodide particles.
Silver Iodide
Silver iodide \textsf{AgI} is a yellowish solid and is an important compound in the realm of colloidal chemistry. Due to its low solubility in water, it readily forms a colloid rather than a true solution. Silver iodide colloids have significant applications, most notably in photography and cloud seeding.

In the problem posed by the textbook, silver iodide colloids are produced as a result of the precipitation reaction between silver nitrate (\textsf{AgNO}\(_3\)) and potassium iodide (KI). When we talk about the 'positively charged sol particles of \textsf{AgI}', we mean that the surface of the silver iodide colloidal particles preferentially adsorbs positively charged ions from the surrounding solution. In this particular case, \textsf{Ag}\(_{+}\) ions are in excess and adhere to the surface of the silver iodide particles, thus bestowing the colloidal system with a positive charge. This charge is key in maintaining the stability of the colloid, as it prevents the particles from aggregating and falling out of solution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Among the following, which is the correct statement about milk? (a) Milk is an emulsion of liquid fat in water (b) Milk in emulsion of protein in water (c) Milk is stabilized by protein (d) Milk is stabilized by fat

The correct match is $$ \begin{array}{ll} \hline \text { Column I } & \text { Column II } \\ \hline \text { (1) Coagulation } & \text { (P) } \begin{array}{l} \text { Scattering of } \\ \text { light } \end{array} \\ \text { (2) Peptization } & \text { (Q) } \begin{array}{l} \text { Purification } \\ \text { of colloidal } \\ \text { solution } \end{array} \\ \begin{array}{ll} \text { (3) } \text { Tyndall } \\ \text { effect } \end{array} & \text { (R) } \begin{array}{l} \text { Addition of an } \\ \text { electrolyte } \end{array} \\ \text { (4) Dialysis } & \text { (S) } \begin{array}{l} \text { Precipitation } \\ \text { of colloidal } \\ \text { solution } \end{array} \\ \hline \end{array} $$ $$\begin{array}{llll}1 & 2 & 3 & 4\end{array}$$ (a) \(\begin{array}{llll}\mathrm{P} & \mathrm{Q} & \mathrm{R} & \mathrm{S}\end{array}\) (b) \(\begin{array}{llll}\mathrm{S} & \mathrm{R} & \mathrm{P} & \mathrm{Q}\end{array}\) (c) \(\begin{array}{llll}\mathrm{R} & \mathrm{S} & \mathrm{Q} & \mathrm{P}\end{array}\) (d) Q \(\mathrm{R} \quad \mathrm{P} \quad \mathrm{S}\)

The simplest way to check whether a system is colloidal is by (a) Tyndall effect (b) Brownian movement (c) Electro dialysis (d) Finding out particle size

In the Ostwald's process for the manufacture of \(\mathrm{HNO}_{3}\), the catalyst used is (a) \(\mathrm{Fe}\) (b) \(\mathrm{Pt}\) (c) \(\mathrm{V}_{2} \mathrm{O}_{5}\) (d) Mo

An emulsion is a colloidal solution consisting of (a) two solids (b) two liquids (c) two gases (d) one solid and one liquid

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free