Chapter 13: Problem 171
The magnetic moment of \(\mathrm{Ni}^{\mathrm{x}+}\) ion \((Z=28)\) is about \(2.82 \mathrm{~B} . \mathrm{M} .\) The value of \(x\) is (a) 2 (b) 4 (c) 1 (d) 3
Short Answer
Expert verified
The value of x is 2, so the correct answer is (a) 2.
Step by step solution
01
Calculate the number of unpaired electrons
The magnetic moment \( \mu \) in Bohr Magneton (BM) is given by the formula \( \mu = \sqrt{n(n+2)} \), where \( n \) is the number of unpaired electrons. Given \( \mu = 2.82 \) BM, we can set up the equation \( 2.82 = \sqrt{n(n+2)} \).
02
Solve for the number of unpaired electrons
Square both sides to get rid of the square root: \( (2.82)^2 = n(n+2) \). Calculating the left side gives \( 7.9524 \approx n^2 + 2n \). This quadratic equation can be solved using factoring, completing the square, or the quadratic formula. Let's estimate the value of \( n \) since it must be an integer and must fit the equation \( n(n+2) \).
03
Estimate the integer value for the number of unpaired electrons
Through trial and error or estimation, we can see that \( n = 1 \) gives \( 1(1+2) = 3 \) and \( n = 2 \) gives \( 2(2+2) = 8 \) which is close to 7.9524. Since the actual number of unpaired electrons must be an integer and \( n = 2 \) fits closely, we have found the number of unpaired electrons.
04
Determine the oxidation state
Nickel (Ni) has an atomic number (Z) of 28, indicating it has 28 electrons. In its neutral state, Ni's electron configuration ends in \( 3d^8 4s^2 \). With two unpaired electrons as calculated, the configuration would be \( 3d^8 \), which suggests a loss of 2 electrons, the \( 4s \) electrons. This would correspond to an oxidation state of +2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bohr Magneton
Understanding the Bohr Magneton (BM) is crucial in the field of magnetic moments in chemistry. It is named after the physicist Niels Bohr and is the fundamental physical constant expressing the magnetic moment of an electron caused by its orbital motion around the nucleus. The magnitude of this moment is defined as one Bohr Magneton, which is approximately equal to \(9.274 \times 10^{-24}\) Joule per Tesla.
In layman's terms, think of the Bohr Magneton as a unit to measure how 'magnetic' an electron can be in its orbit. When scientists measure the magnetic properties of an atom, they often express this value in terms of BM. Especially in problems concerning transition metals like Nickel (Ni), BM is of particular importance as these metals can have variable magnetic moments depending on their electron configurations and the presence of unpaired electrons.
In layman's terms, think of the Bohr Magneton as a unit to measure how 'magnetic' an electron can be in its orbit. When scientists measure the magnetic properties of an atom, they often express this value in terms of BM. Especially in problems concerning transition metals like Nickel (Ni), BM is of particular importance as these metals can have variable magnetic moments depending on their electron configurations and the presence of unpaired electrons.
Oxidation State Calculation
The concept of oxidation states is akin to accounting for the electrons in an atom: it tells us about the hypothetical charge an atom would have if all its bonds were completely ionic. Calculating the oxidation state of an element in a compound or ion involves using certain rules, such as the fact that the sum of oxidation states must equal the overall charge of the compound or ion.
In relation to our Ni example, by knowing the electronic configuration and the number of unpaired electrons, chemists can deduce the oxidation state of the metal ion. For transition metals, the oxidation state can reveal the type of chemical reactions it may undergo and its magnetic properties. This calculation is pivotal when working with coordination compounds, catalysis, and materials science.
In relation to our Ni example, by knowing the electronic configuration and the number of unpaired electrons, chemists can deduce the oxidation state of the metal ion. For transition metals, the oxidation state can reveal the type of chemical reactions it may undergo and its magnetic properties. This calculation is pivotal when working with coordination compounds, catalysis, and materials science.
Unpaired Electrons Determination
The determination of unpaired electrons is a vital step when solving magnetic moment problems. Unpaired electrons are the electrons in an atom or ion that are not part of a pair. When electrons are paired together, their spin cancel out each other's magnetic moments, rendering the atom diamagnetic. However, when electrons are unpaired, they contribute to paramagnetism since their spins generate magnetic fields.
To calculate the number of unpaired electrons, we use the formula \( \text{magnetic moment } (\mu) = \sqrt{n(n+2)} \), where \( n \) is the number of unpaired electrons. By analyzing the magnetic moment data, chemists can infer the arrangement of electrons within an atom's or ion's electron shells. This knowledge is leveraged to understand and predict the behavior of the substance under study in terms of its reactivity, color, and magnetic properties.
To calculate the number of unpaired electrons, we use the formula \( \text{magnetic moment } (\mu) = \sqrt{n(n+2)} \), where \( n \) is the number of unpaired electrons. By analyzing the magnetic moment data, chemists can infer the arrangement of electrons within an atom's or ion's electron shells. This knowledge is leveraged to understand and predict the behavior of the substance under study in terms of its reactivity, color, and magnetic properties.