Chapter 14: Problem 58
In the reaction: \({ }_{4} \mathrm{Be}^{9}+\mathrm{X} \rightarrow{ }_{5} \mathrm{~B}^{10}+\gamma, \mathrm{X}\) is (a) proton (b) deuteron (c) \(\alpha\) -particle (d) neutron
Short Answer
Expert verified
The particle X is a proton.
Step by step solution
01
- Understanding the Reaction
First, we must understand that this reaction is a nuclear reaction, where one element is transformed into another. In this reaction, Beryllium-9 ({}_{4} Be^{9}) absorbs a particle X and is transformed into Boron-10 ({}_{5} Boron^{10}) while releasing a gamma photon (gamma). We need to identify the particle X based on the law of conservation of mass and atomic numbers.
02
- Applying Conservation of Mass
According to the conservation of mass, the mass number on the left side of the reaction must equal the mass number on the right side. The mass number of Beryllium is 9, and the mass number of Boron is 10, so the mass number of particle X must be 1.
03
- Applying Conservation of Charge
According to the conservation of charge, the atomic number (or the number of protons) on the left side of the reaction must equal the atomic number on the right side. The atomic number of Beryllium is 4, and the atomic number of Boron is 5. Therefore, the particle X must contribute an atomic number of 1.
04
- Determining the Particle
From Steps 2 and 3, we can deduce that the unknown particle X must have a mass number of 1 and an atomic number of 1. The particle that has these characteristics is the proton, so the correct answer is (a) proton.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conservation of Mass
In the realm of nuclear chemistry, the concept of conservation of mass plays a pivotal role. It is an extension of the principle originally formulated by Antoine Lavoisier, which states that mass is neither created nor destroyed in an isolated system. Translated to nuclear reactions, this means that the sum of the mass numbers before the reaction must equal the sum after the reaction.
Let's consider a textbook exercise where Beryllium-9 undergoes a transformation. According to conservation of mass, if Beryllium with a mass number of 9 changes, then the mass number of the resulting element plus the mass number of the emitted or absorbed particle must also total 9. In our example, Boron has a mass number of 10, indicating that the particle being absorbed has a mass number of 1 to account for the extra mass in the product.
Let's consider a textbook exercise where Beryllium-9 undergoes a transformation. According to conservation of mass, if Beryllium with a mass number of 9 changes, then the mass number of the resulting element plus the mass number of the emitted or absorbed particle must also total 9. In our example, Boron has a mass number of 10, indicating that the particle being absorbed has a mass number of 1 to account for the extra mass in the product.
Conservation of Charge
Equally fundamental to understanding nuclear reactions is the conservation of charge. This law asserts that the total charge before and after a nuclear reaction must remain constant. Nuclear reactions involve changes in an atom's nucleus, often resulting in the transformation of one element into another. However, these changes must comply with the rule that the sum of atomic numbers, which corresponds to the number of protons and therefore the charge of the nucleus, remains unchanged.
As an illustration, in the provided exercise, we have Beryllium-9 with 4 protons transforming into Boron-10 with 5 protons. For the charges to balance, the particle that Beryllium absorbs must carry a charge equivalent to 1 proton. This helps us narrow down the identity of the absorbed particle, as it must have a positive charge to satisfy the conservation of charge.
As an illustration, in the provided exercise, we have Beryllium-9 with 4 protons transforming into Boron-10 with 5 protons. For the charges to balance, the particle that Beryllium absorbs must carry a charge equivalent to 1 proton. This helps us narrow down the identity of the absorbed particle, as it must have a positive charge to satisfy the conservation of charge.
Nuclear Reactions
Nuclear reactions are processes that alter the composition, energy, or structure of an atomic nucleus. Unlike chemical reactions, which involve the electrons surrounding the nucleus, nuclear reactions can change one element into another. This occurs through the addition or release of particles such as protons, neutrons, alpha particles, or others.
For instance, in our exercise, a nuclear reaction involves Beryllium capturing a particle to become Boron, while also emitting a gamma ray. This differs from a chemical reaction as the identity of the element itself changes. Nuclear reactions must obey the laws of conservation of mass and charge, which help us ascertain the identity of particles involved in these reactions and predict the products. In the context of our example, we used these conservation laws to identify that the absorbed particle is a proton—transforming Beryllium-9 into Boron-10 and aligning with what we know about these fundamental nuclear principles.
For instance, in our exercise, a nuclear reaction involves Beryllium capturing a particle to become Boron, while also emitting a gamma ray. This differs from a chemical reaction as the identity of the element itself changes. Nuclear reactions must obey the laws of conservation of mass and charge, which help us ascertain the identity of particles involved in these reactions and predict the products. In the context of our example, we used these conservation laws to identify that the absorbed particle is a proton—transforming Beryllium-9 into Boron-10 and aligning with what we know about these fundamental nuclear principles.