Chapter 4: Problem 24
The minimum work which must be done to compress \(16 \mathrm{~g}\) of oxygen isothermally, at \(300 \mathrm{~K}\) from a pressure of \(1.01325\) \(\times 10^{3} \mathrm{~N} / \mathrm{m}^{2}\) to \(1.01325 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}\) is \((\ln 100=4.6, R=8.3 \mathrm{~J} / \mathrm{K}-\mathrm{mol})\) (a) \(5727 \mathrm{~J}\) (b) \(11.454 \mathrm{~kJ}\) (c) \(123.255 \mathrm{~kJ}\) (d) \(1232.55 \mathrm{~J}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.