The maximum high temperature molar heat capacity at constant volume to be expected for acetylene which is a linear molecule is (a) 9 cal/deg-mole (b) \(12 \mathrm{cal} /\) deg-mole (c) \(19 \mathrm{cal} /\) deg-mole (d) \(14 \mathrm{cal} /\) deg-mole

Short Answer

Expert verified
The maximum high temperature molar heat capacity at constant volume for acetylene, a linear molecule, is expected to be 14 cal/deg-mole.

Step by step solution

01

Determine degrees of freedom for acetylene

Identify that acetylene, a diatomic linear molecule, has a total of 5 degrees of freedom at high temperatures: 2 rotational, 2 vibrational, and 1 translational.
02

Calculate molar heat capacity at constant volume

Use the equipartition theorem which states that each degree of freedom contributes \(\frac{1}{2} R\) to the molar heat capacity at constant volume. With 5 degrees of freedom and \(R \approx 2 \mathrm{cal}/\text{deg-mole}\), the total molar heat capacity at constant volume \(C_v\) is \(5 \times \frac{1}{2} R = \frac{5}{2} R = \frac{5}{2} \times 2 \mathrm{cal}/\text{deg-mole}\).
03

Compute the final answer

Multiply \(\frac{5}{2}\) by 2 to get the maximum high temperature molar heat capacity at constant volume for acetylene, which yields a result of 5 cal/deg-mole. Since this is not one of the answer choices, consider the possibility that vibrational degrees of freedom might be counted differently.
04

Reassess vibrational degrees of freedom

At high temperatures, each vibrational mode is counted as two degrees of freedom (one for the kinetic energy and one for the potential energy), which brings the total to 7 degrees of freedom for acetylene (2 rotational, 4 vibrational, 1 translational).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
In the study of thermodynamics and statistical mechanics, 'degrees of freedom' refer to the number of independent ways in which a system can possess energy. For a molecule, these include translational, rotational, and vibrational movements. Translational degrees describe the movement of the molecule as a whole in three-dimensional space, accounting for three degrees of freedom (one for each axis of movement - x, y, and z). Rotational degrees account for the molecule's orientation in space. For linear molecules like acetylene, there are two rotational degrees since rotation along the bond axis does not change the system's energy state. Vibrational degrees are related to the internal vibrations of a molecule's atoms and require a more complex approach for quantification.

Considering the example of acetylene, we can simplify the complex nature of molecular motion into these quantifiable degrees of freedom. At high temperatures, notably, certain degrees disclosed in the problem must be reassessed to accurately represent the molar heat capacity. As seen in the exercise, counting vibrational modes correctly—as two degrees of freedom—is crucial to calculating the correct molar heat capacity.
Equipartition Theorem
The equipartition theorem is a fundamental concept in classical thermodynamics that states energy is distributed equally among its degrees of freedom. According to this theorem, for each degree of freedom that contributes to a system's energy, an amount of energy equal to \frac{1}{2}kT\ is granted, where \(k\) is the Boltzmann constant and \(T\) is the temperature. When dealing with molar heat capacities, the ideal gas constant \(R\) is used instead of the Boltzmann constant as it pertains to one mole of substance.

In practical terms, this means that for a diatomic linear molecule like acetylene, each degree of freedom would contribute \(\frac{1}{2} R\) to the molar heat capacity at constant volume. Thus, the problem's solution method hinges on correctly identifying and incorporating the degrees of freedom using the equipartition theorem. This helps explain why a miscalculation in the number of degrees of freedom can lead to a significant error in determining the molar heat capacity.
Vibrational Modes
Vibrational modes of a molecule refer to the patterns of motion that involve periodic motion of the atoms within the molecule with respect to their equilibrium positions. Every molecule can vibrate in different ways, and each distinct pattern represents a vibrational mode. A linear molecule with \(N\) atoms has \(3N-5\) vibrational modes, while a nonlinear molecule has \(3N-6\).

For diatomic molecules or linear polyatomic molecules such as acetylene, vibrations can occur along the bond axis (stretching) or involve changes in the bond angle (bending), although for a diatomic molecule, only the stretching mode is present. It's essential to recognize that at high temperatures each vibrational mode is doubled due to the contribution of both kinetic and potential energy. This distinction is crucial and was underscored in the exercise, where each vibrational degree of freedom at high temperatures contributes as two degrees, highlighting the pivotal role of vibrational modes in calculating the molar heat capacity of a molecule.

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Most popular questions from this chapter

An amount of 5 mole \(\mathrm{H}_{2} \mathrm{O}(1)\) at \(100^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) is converted into \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) at \(100^{\circ} \mathrm{C}\) and 5 atm. \(\Delta G\) for the process is (a) zero (b) \(1865 \ln 5 \mathrm{cal}\) (c) \(3730 \ln 5 \mathrm{cal}\) (d) \(-3730 \ln 5 \mathrm{cal}\)

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Molar heat capacity of \(\mathrm{CD}_{2} \mathrm{O}\) (deuterated form of formaldehyde) vapour at constant pressure is vapour 14 cal/K-mol. The entropy change associated with the cooling of \(3.2 \mathrm{~g}\) of \(\mathrm{CD}_{2} \mathrm{O}\) vapour from \(1000 \mathrm{~K}\) to \(900 \mathrm{~K}\) at constant pressure is (assume ideal gas behaviour for \(\mathrm{CD}_{2} \mathrm{O}\) ) \([\ln 0.9=-0.1]\) (a) \(+0.14 \mathrm{cal} / \mathrm{K}\) (b) \(-0.14 \mathrm{cal} / \mathrm{K}\) (c) \(-1.4 \mathrm{cal} / \mathrm{K}\) (d) \(+1.4 \mathrm{cal} / \mathrm{K}\)

The pressure and density of a diatomic gas \((\gamma=7 / 5)\) change from \(\left(P_{1}, d_{1}\right)\) to \(\left(P_{2},\right.\), \(d_{2}\) ) adiabatically. If \(d_{2} / d_{1}=32\), then what is the value of \(P_{2} / P_{1}\) ? (a) 32 (b) 64 (c) 128 (d) 256

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