Equal volumes of one molar hydrochloric acid and one molar sulphuric acid are neutralized completely by dilute \(\mathrm{NaOH}\) solution by which \(X\) and \(Y\) kcal of heat are liberated, respectively. Which of the following is true? (a) \(X=Y\) (b) \(2 X=Y\) (c) \(X=2 Y\) (d) none of these

Short Answer

Expert verified
The correct answer is (b) \(2X=Y\). For strong acids and bases, the heat of neutralization is constant per mole of water produced, resulting in twice as much heat for the neutralization of H2SO4 compared to HCl when equal volumes of one molar solutions are used.

Step by step solution

01

Examine the Reactions

Analyze the neutralization reactions for hydrochloric acid (HCl) and sulphuric acid (H2SO4) when they react with sodium hydroxide (NaOH).For hydrochloric acid: \(\text{HCl}(aq) + \text{NaOH}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l)\).For sulphuric acid: \(\text{H}_2\text{SO}_4(aq) + 2\text{NaOH}(aq) \rightarrow \text{Na}_2\text{SO}_4(aq) + 2\text{H}_2\text{O}(l)\).
02

Calculate Moles of NaOH

Because the acids are both one molar solutions, and since the volumes are equal, the moles of NaOH required to neutralize one mole of HCl and one mole of H2SO4 will differ. Specifically, it will take 1 mole of NaOH to neutralize 1 mole of HCl and 2 moles of NaOH to neutralize 1 mole of H2SO4.
03

Understand Heat of Neutralization

The heat of neutralization is the heat change that occurs when one equivalent of an acid and one equivalent of a base undergo a neutralization reaction to form water and a salt. Once standard conditions are specified, the heat of neutralization is relatively constant for strong acid-strong base reactions, which typically release 13.7 kcal per equivalent of acid or base.
04

Relate Moles of NaOH to Heat Liberated

From the previous step, we know that the amount of NaOH needed to neutralize H2SO4 is twice that for HCl, hence the reaction with H2SO4 will liberate twice as much heat. If \(X\) kcal is the heat liberated by neutralizing HCl, then neutralizing H2SO4 will liberate \(2X\) kcal because it involves twice as many moles of NaOH.
05

Choose the Correct Answer

Accordingly, the amount of heat liberated when dilute NaOH solution completely neutralizes equal volumes of one molar HCl is \(X\), and for one molar H2SO4, it is \(2X\). Thus, option (b) \(2X=Y\) is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutralization Reactions
When we talk about neutralization reactions, we refer to the chemical process where an acid and a base react to form water and a salt. This reaction is quintessential in understanding how different substances can combine to form completely new products. For instance, in our exercise, hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to produce sodium chloride (NaCl) and water (H2O). Similarly, sulphuric acid (H2SO4) reacts with NaOH to produce sodium sulphate (Na2SO4) and water. The unique characteristic of these reactions is the idea of equivalence - it takes exact amounts of acid and base to achieve a neutral solution, meaning the solution has a pH of 7. In the course of these neutralization processes, energy is released in the form of heat, which can be measured and is a topic of interest in calorimetry studies.

Understanding these reactions requires comprehension of the ratio in which the reactants combine, which is dictated by their respective chemical formulas. HCl combines with NaOH in a 1:1 ratio, whereas H2SO4 requires twice the amount of NaOH because it contains two replaceable hydrogen ions per molecule, resulting in a 1:2 ratio.
Enthalpy Change
Enthalpy change, often expressed as \( \Delta H \), is a term used in chemistry to describe the amount of heat absorbed or released during a chemical reaction at constant pressure. When a reaction occurs, bonds are broken and formed, which involves energy. If the reaction releases heat, it is exothermic, and the enthalpy change is negative. On the contrary, if the reaction absorbs heat, it is endothermic, and the enthalpy change is positive.

In the context of neutralization reactions, these tend to be exothermic. For strong acid and base pairs, the enthalpy change is fairly constant, often releasing around 13.7 kcal/mol of reactants. This consistent release of energy is due to the formation of water from H+ ions and OH ions. Moreover, this provides us with a way to measure the strength of an acid or base: by calculating the heat liberated during the neutralization, we gain insight into their reactivity and behavior in solution.
Stoichiometry
Stoichiometry is the section of chemistry that pertains to the calculation of reactants and products in chemical reactions. It is the backbone of reactions, providing the quantitative relationship between the amounts of substances involved. Through stoichiometry, we determine the proportional ratios needed to react completely without any excess of either reactant.

In our exercise, stoichiometry plays a critical role in understanding why sulphuric acid (H2SO4) releases twice the heat compared to hydrochloric acid (HCl) when reacting with sodium hydroxide (NaOH). It all comes down to the stoichiometric coefficients: two moles of NaOH are required to completely neutralize one mole of H2SO4 due to the presence of two acidic protons in the sulphuric acid molecule. Therefore, the stoichiometry tells us that the number of heat units released in the reaction against sulphuric acid would be double that of hydrochloric acid.
Acid-Base Reactions
Acid-base reactions, known as neutralizations, are fundamental chemical processes where hydrogen ions, H+ (protons), from the acid react with hydroxide ions, OH, from the base to form water molecules. An acid is a substance that can donate a proton, while a base is a substance that can accept a proton.

These reactions can be represented by a general equation: acid + base → salt + water. What is interesting about these reactions is that a strong acid like hydrochloric acid (HCl) will react vigorously with a strong base like sodium hydroxide (NaOH), resulting in a significant heat release. This is why measuring the heat of neutralization is a practical way to examine the strength and behavior of acids and bases in chemical reactions. Remember, a 'strong' acid or base is one that completely dissociates in solution, so the concentration of H+ or OH ions in a solution of a strong acid or base is equal to the concentration of the acid or base itself.

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Most popular questions from this chapter

The heat capacity of bomb calorimeter is \(500 \mathrm{~J} /{ }^{\circ} \mathrm{C}\). A \(2{ }^{\circ} \mathrm{C}\) rise in temperature has been observed on the combustion of \(0.1 \mathrm{~g}\) of methane. What is the value of \(\Delta E\) per mole of methane? (a) \(1 \mathrm{~kJ}\) (b) \(160 \mathrm{~kJ}\) (c) \(-160 \mathrm{~kJ}\) (d) \(-1 \mathrm{~kJ}\)

As a \(0.1\) mole sample of solid \(\mathrm{NH}_{4} \mathrm{Cl}\) was dissolved in \(50 \mathrm{ml}\) of water, the temperature of the solution decreased. A small electrical immersion heater restored the temperature of the system by passing \(0.125 \mathrm{~A}\) from a \(15 \mathrm{~V}\) power supply for a period of 14 min. \(\Delta H\) for the process: \(\mathrm{NH}_{4} \mathrm{Cl}(\mathrm{s}) \rightarrow \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{aq})\) is (a) \(-15.75 \mathrm{~kJ}\) (b) \(+15.75 \mathrm{~kJ}\) (c) \(-787.5 \mathrm{~J}\) (d) \(+787.5 \mathrm{~J}\)

The intermediate \(\mathrm{SiH}_{2}\) is formed in the thermal decomposition of silicon hydrides. Calculate \(\Delta H_{\mathrm{f}}^{\circ}\) of \(\mathrm{SiH}_{2}\) from the following reactions: \(\mathrm{Si}_{2} \mathrm{H}_{6}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{SiH}_{4}(\mathrm{~g})\) \(\Delta H^{\circ}=-11.7 \mathrm{~kJ} / \mathrm{mol}\) \(\mathrm{SiH}_{4}(\mathrm{~g}) \rightarrow \mathrm{SiH}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\) \(\Delta H^{\circ}=+239.7 \mathrm{~kJ} / \mathrm{mol}\) \(\Delta H_{\mathrm{f}}^{\circ}, \mathrm{Si}_{2} \mathrm{H}_{6}(\mathrm{~g})=+80.3 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (a) \(353 \mathrm{~kJ} / \mathrm{mol}\) (b) \(321 \mathrm{~kJ} / \mathrm{mol}\) (c) \(198 \mathrm{~kJ} / \mathrm{mol}\) (d) \(274 \mathrm{~kJ} / \mathrm{mol}\)

The \(\Delta_{f} H^{\circ}\) for \(\mathrm{CO}_{2}(\mathrm{~g}), \mathrm{CO}(\mathrm{g})\) and \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) are \(-393.5,-110.5\) and \(-241.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\), respectively. The standard enthalpy change (in \(\mathrm{kJ}\) ) for the reaction: \(\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) is (a) \(524.1\) (b) \(41.2\) (c) \(-262.5\) (d) \(-41.2\)

Which of the following salts shall cause more cooling when one mole of the salt is dissolved in the same amount of water? (Integral heat of solution at \(298 \mathrm{~K}\) is given for each solute.) (a) \(\mathrm{KNO}_{3} ; \Delta H=35.4 \mathrm{~kJ} / \mathrm{mol}\) (b) \(\mathrm{NaCl} ; \Delta H=5.35 \mathrm{~kJ} / \mathrm{mol}\) (c) \(\mathrm{KOH} ; \Delta H=-55.6 \mathrm{~kJ} / \mathrm{mol}\) (d) \(\mathrm{HBr} ; \Delta H=-83.3 \mathrm{~kJ} / \mathrm{mol}\)

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