Chapter 5: Problem 67
Sublimation energy of \(\mathrm{Ca}\) is \(121 \mathrm{~kJ} / \mathrm{mol}\). Dissociation energy of \(\mathrm{Cl}_{2}\) is \(242.8 \mathrm{~kJ} / \mathrm{mol}\), the total ionization energy of \(\mathrm{Ca}(\mathrm{g})\) \(\rightarrow \mathrm{Ca}^{2+}(\mathrm{g})\) is \(2422 \mathrm{~kJ} / \mathrm{mol}\) and electron affinity of \(\mathrm{Cl}\) is \(-355 \mathrm{~kJ} / \mathrm{mol}\). Lattice energy of \(\mathrm{CaCl}_{2}\) is \(-2430.8 \mathrm{~kJ} / \mathrm{mol}\). What is \(\Delta H\) for the process \(\mathrm{Ca}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow \mathrm{CaCl}_{2}(\mathrm{~s})\) ? (a) \(-355 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(+3550 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(-35.5 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(-1720 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Short Answer
Step by step solution
Analyze the Formation of CaCl2
Sublimation of Ca
Dissociation of Cl2
Ionization of Ca
Electron Affinity
Lattice Energy
Calculate the Overall Enthalpy Change
Simplify the Enthalpy Calculation
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