Chapter 6: Problem 21
For the reaction: \(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons\) \(2 \mathrm{NOCl}(\mathrm{g}), \mathrm{NO}\) and \(\mathrm{Cl}_{2}\) are initially taken in mole ratio of \(2: 1 .\) The total pressure at equilibrium is found to be \(1 \mathrm{~atm}\). If the moles of \(\mathrm{NOCl}\) are one-fourth of that of \(\mathrm{Cl}_{2}\) at equilibrium, \(K_{\mathrm{p}}\) for the reaction is (a) \(\frac{13}{36}\) (b) \(\frac{13}{256}\) (c) \(\frac{13}{512}\) (d) \(\frac{13}{128}\)
Short Answer
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