Chapter 10: Q. 10.63 (page 355)

At rest, the $[H_{3} O^{+}]$ of the stomach fluid is $2.0 \times 10^{- 4} M$ . What is the $pH$ of the stomach fluid?

Short Answer

Expert verified

The pH text of the stomach fluid is 3.70.

Step by step solution

Step - 1 Introduction

The solution's $pH$ can be defined as the negative logarithmic (base 10) of the $[H_{3} O^{+}]$ concentration .

$pH = - \log [H_{3} O^{+}]$

$pOH = - \log [{OH}^{-}]$

$pH + pOH = 14$

Step - 2 Explanation

The solution has an acid concentration of $2.0 \times 10^{- 4} M$ . Calculate the solution's $pH$ using the following formula:

p H = - \log [H_{3} O^{*}]

$= - \log [2.0 \times 10^{- 4}]$

$= 4 - \log (2.0)$

$= 3.70$

As a result, the pH text of the stomach fluid is 3.70.

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At rest, the $[H_{3} O^{+}]$ of the stomach fluid is $2.0 \times 10^{- 4} M$ . What is the $pH$ of the stomach fluid?

Short Answer

Step by step solution

Step - 1 Introduction

Step - 2 Explanation

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At rest, the H3O+of the stomach fluid is 2.0×10-4M. What is thepH of the stomach fluid?

Short Answer

Step by step solution

Step - 1 Introduction

Step - 2 Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Chemical Analysis

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Organic Chemistry

Kinetics

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Study anywhere. Anytime. Across all devices.

At rest, the $[H_{3} O^{+}]$ of the stomach fluid is $2.0 \times 10^{- 4} M$ . What is the $pH$ of the stomach fluid?