Chapter 10: Q. 10.64 (page 355)

When food enters the stomach, $HCl$ is released and the $[H_{3} O^{+}]$ of the stomach fluid rises to $4 \times 10^{- 2} M$ . What is the $pH$ of the stomach fluid?

Short Answer

Expert verified

The gastric fluid's pH text is 1.4.

Step by step solution

Step - 1 Given information

The solution's $pH$ can be defined as the negative logarithmic (base 10) of the $[H_{3} O^{+}]$ concentration.

$pH = - \log [H_{3} O^{+}]$

$pOH = - \log [{OH}^{-}]$

$pH + pOH = 14$

step - 2 Explanation

The stomach fluid concentration is $2.0 \times 10^{- 4} M$ . Use the following formula to calculate the $pH$ solution:

$p H = - \log [H_{3} O^{+}]$

$= - \log [4.0 \times 10^{- 2}]$

$= 2 - \log (4.0)$

$= 2 - 0.6$ 0

$= 1.4$

As a result, the stomach fluid's pH text is 1.4.

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When food enters the stomach, $HCl$ is released and the $[H_{3} O^{+}]$ of the stomach fluid rises to $4 \times 10^{- 2} M$ . What is the $pH$ of the stomach fluid?

Short Answer

Step by step solution

Step - 1 Given information

step - 2 Explanation

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When food enters the stomach,HCl is released and the H3O+ of the stomach fluid rises to 4×10-2M. What is the pH of the stomach fluid?

Short Answer

Step by step solution

Step - 1 Given information

step - 2 Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

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Study anywhere. Anytime. Across all devices.

When food enters the stomach, $HCl$ is released and the $[H_{3} O^{+}]$ of the stomach fluid rises to $4 \times 10^{- 2} M$ . What is the $pH$ of the stomach fluid?