Chapter 10: Q. 10.66 (page 355)

After Larry had taken Nexium for 4 weeks, the $pH$ in his stomach was raised to 4.52. What is the $[H_{3} O^{+}]$ in his stomach?

Short Answer

Expert verified

The $[H_{3} O^{+}]$ concentration in stomach is $3.02 \times 10^{- 5} M$

Step by step solution

Step - 1 Given information

The pH of a solution can be calculated using the negative logarithmic base value 10 is the $[H_{3} O^{+}]$ focus.

$pH = - \log [H_{3} O^{+}]$

$pOH = - \log [{OH}^{-}]$

$pH + pOH = 14$

Step - 2 Explanation

The elevated pH in the stomach is 4.52. Calculate the Using the following formula, calculate the $[H_{3} O^{*}]$ concentration:

$p H = - \log [H_{3} O^{+}]$

$4.52 = - \log [H_{3} O^{+}]$

$[H_{3} O^{*}] = 10^{(- 4.52)}$

$[H_{3} O^{*}] = 3.02 \times 10^{- 5} M$

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After Larry had taken Nexium for 4 weeks, the $pH$ in his stomach was raised to 4.52. What is the $[H_{3} O^{+}]$ in his stomach?

Short Answer

Step by step solution

Step - 1 Given information

Step - 2 Explanation

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After Larry had taken Nexium for 4 weeks, the pHin his stomach was raised to 4.52. What is the H3O+in his stomach?

Short Answer

Step by step solution

Step - 1 Given information

Step - 2 Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Organic Chemistry

Chemistry Branches

Making Measurements

Inorganic Chemistry

Ionic and Molecular Compounds

Study anywhere. Anytime. Across all devices.

After Larry had taken Nexium for 4 weeks, the $pH$ in his stomach was raised to 4.52. What is the $[H_{3} O^{+}]$ in his stomach?