Chapter 10: Q.10.92 (page 360)

Calculate the $[H_{3} O^{+}] a n d [{OH}^{-}]$ for a solution with the following pH values:
a. 10.0
b. 5.0
c. 7.00
d. 6.5

Short Answer

Expert verified

Part a. $[H_{3} O^{+}] = 1.0 \times 10^{- 10} M, [{OH}^{-}] = 1 \times 10^{- 4} M$

Part b. $[H_{3} O^{+}] = 1.0 \times 10^{- 5} M, [{OH}^{-}] = 1 \times 10^{- 9} M$

Part c. $[H_{3} O^{+}] = 1.0 \times 10^{-} 7 M, [{OH}^{-}] = 1 \times 10^{- 7} M$

Part d. $[H_{3} O^{+}] = 1.51 \times 10^{- 2} M, [{OH}^{-}] = 6.6 \times 10^{- 13} M$

Step by step solution

Given Information (Part a)

As a solution gets more acidic as H+ increases, the pH diminishes. As a solution gets more basic (higher [OH-]), the pH increases. As the pH of a solution diminishes by one pH unit, the concentration of H+ increases by ten times

Explanation Part (a)

Given, pH = $10$

We know, pH = -log

$[H_{3} O^{+}] = 10^{- pH}$ and $[H_{3} O^{+}] [{OH}^{-}] = 1 \times 10^{- 14}$

$\Rightarrow [H_{3} O^{+}] = 10^{- 10} = 1.0 \times 10^{- 10} M$

$[{OH}^{-}] = \frac{1.0 \times 10^{- 14}}{1.0 \times 10^{10}} = 1 \times 10^{- 4} M$

Explanation Part (b)

Given pH = $5$

We know, pH = -log

$\begin{aligned} [H_{3} O^{+}] = 10^{- pH} and [H_{3} O^{+}] [{OH}^{-}] = 1 \times 10^{- 14} \end{aligned}$

$\Rightarrow [H_{3} O^{+}] = 10^{- 5}$

$= 1.0 \times 10^{- 5} M$

$\begin{aligned} [{OH}^{-}] = \frac{1.0 \times 10^{- 14}}{1.0 \times 10^{- 5}} = 1 \times 10^{- 9} M \end{aligned}$

Explanation Part (c)

Given pH = $7$

We know, pH = -log
$\begin{aligned} [H_{3} O^{+}] = 10^{- pH} and [H_{3} O^{+}] [{OH}^{-}] = 1 \times 10^{- 14} \end{aligned}$

$\Rightarrow [H_{3} O^{+}] = 10^{- 7}$ $= 1.0 \times 10^{- 7} M$

$\begin{aligned} [{OH}^{-}] = \frac{1.0 \times 10^{- 14}}{1.0 \times 10^{- 7}} = 1 \times 10^{- 7} M \end{aligned}$

Explanation Part (d)

Given pH = $1.82$

We know, pH = -log

$[H_{3} O^{+}] = 10^{- pH} and [H_{3} O^{+}] [{OH}^{-}] = 1 \times 10^{- 14}$

$\Rightarrow [H_{3} O^{+}] = 10^{- 1.82}$

$= 1.51 \times 10^{- 2} M$

$\begin{aligned} [{OH}^{-}] = \frac{1.0 \times 10^{- 14}}{1.51 \times 10^{- 2}} = 6.6 \times 10^{- 13} M \end{aligned}$

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Calculate the $[H_{3} O^{+}] a n d [{OH}^{-}]$ for a solution with the following pH values:
a. 10.0
b. 5.0
c. 7.00
d. 6.5

Short Answer

Step by step solution

Given Information (Part a)

Explanation Part (a)

Explanation Part (b)

Explanation Part (c)

Explanation Part (d)

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Calculate the H3O+andOH−for a solution with the following pH values: a. 10.0b. 5.0c. 7.00d. 6.5

Short Answer

Step by step solution

Given Information (Part a)

Explanation Part (a)

Explanation Part (b)

Explanation Part (c)

Explanation Part (d)

One App. One Place for Learning.

Most popular questions from this chapter

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Calculate the $[H_{3} O^{+}] a n d [{OH}^{-}]$ for a solution with the following pH values:
a. 10.0
b. 5.0
c. 7.00
d. 6.5