Chapter 12: Q. 12.32 (page 420)

Draw the condensed structural formulas for the aldehyde and carboxylic acid produced when each of the following is oxidized:

Short Answer

Expert verified

a. $C_{4} H_{7} - {CH}_{2} - OH (Cyclobutylmethanol)$ first oxidized to $C_{4} H_{7} - CHO (Cyclobutyl - methanal)$ and it further oxidized to $C_{4} H_{7} - COOH (Cyclobutyl - methanoic acid)$ .

b. ${CH}_{3} - OH (Methanol)$ first oxidized to $HCHO (Methanal)$ and it further oxidized to $HCOOH (Methanoic acid)$ .

c. ${CH}_{2} Cl - {CH}_{2} - {CH}_{2} OH (3 - chloro - 1 - propanol)$ first oxidized to ${CH}_{2} Cl - {CH}_{2} - CHO (3 - Chloro - 1 - propanal)$ and it further oxidized to ${CH}_{2} Cl - {CH}_{2} - COOH (3 - Chloro - 1 - propanoic acid)$ .

Step by step solution

Part(a) Step 1: Given information

We need to draw the condensed structural formula for the aldehyde and carboxylic acid produced when Cyclobutyl-methanol is oxidized.

Part(a) Step 2: Explanation

In organic chemistry, alcohol oxidation is a crucial process. Aldehydes and carboxylic acids can be made by oxidizing primary alcohols.

Given, $C_{4} H_{7} - {CH}_{2} - OH (Cyclobutylmethanol)$ first oxidizes to $C_{4} H_{7} - CHO (Cyclobutyl - methanal)$ and then oxidizes to $C_{4} H_{7} - COOH (Cyclobutyl - methanoic acid)$ .

Part(b) Step 1: Given information

We need to draw the condensed structural formula for the aldehyde and carboxylic acid produced when ${CH}_{3} - OH$ is oxidized.

Part(b) Step 2: Explanation

In organic chemistry, alcohol oxidation is a crucial process. Aldehydes and carboxylic acids can be made by oxidizing primary alcohols.

Given, ${CH}_{3} - OH (Methanol)$ oxidizes to $HCHO (Methanal)$ .

Methanal oxidizes to $HCOOH (Methanoic acid)$ .

Part(c) Step 1: Given information

We need to draw the condensed structural formula for the aldehyde and carboxylic acid produced when $3 - chloro - 1 - propanol$ is oxidized.

Part(c) Step 2: Explanation

In organic chemistry, alcohol oxidation is a crucial process. Aldehydes and carboxylic acids can be made by oxidizing primary alcohols.

Given, ${CH}_{2} Cl - {CH}_{2} - {CH}_{2} OH (3 - chloro - 1 - propanol)$ oxidizes to ${CH}_{2} Cl - {CH}_{2} - CHO (3 - Chloro - 1 - propanal)$ and it further oxidizes to ${CH}_{2} Cl - {CH}_{2} - COOH (3 - Chloro - 1 - propanoic acid)$ .