Chapter 13: Q. 13.22 (page 446)

Identify each of the following as D or L enantiomer.

Short Answer

Expert verified

Part(a) Arabinose is D enantiomer.

Part(b) Sorbose is L enantiomer.

Part(c) Lyxose is D enantiomer.

Part(d) Ribose is L enantiomer.

Step by step solution

Part (a) Step 1: Given Information

We need to identify Arabinose is D or L enantiomer.

Part (a) Step 2: Explanation

In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the right then the compound is a D-enantiomer.

In the given design of arabinose, the - OH bunch is appended to the base chiral focus and it focuses towards the right. In this way, it's a D-enantiomer.

Part (b) Step 1: Given Information

We need to identify sorbose is D or L enantiomer.

Part (b) Step 2: Explanation

In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the left then the compound is an L-enantiomer.

In the given construction of sorbose, the - OH bunch is connected to the base chiral focus and it focuses towards the left. Hence, it's an L-enantiomer.

Part (c) Step 1: Given Information

We need to identify Lyxose is D or L enantiomer.

Part (c) Step 2: Explanation

In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the right then the compound is a D-enantiomer.

In the given design of lyxose, the - OH bunch is appended to the base chiral focus and it focuses towards the right. In this manner, it's a D-enantiomer.

Part (d) Step 1: Given Information

We need to identify Ribose is D or L enantiomer.

Part (d) Step 2: Explanation

In a natural molecule, if the - OH bunch is joined to the base chiral focus and it focuses towards the left then the compound is an L-enantiomer.

In the given construction of Ribose, the - OH bunch is connected to the base chiral focus and it focuses towards the left. Hence, it's an L-enantiomer.