Calculate the molar mass for each of the following:

a. ${\mathrm{CaSO}}_4$, calcium sulfate, used to make casts to protect broken bones

b. ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$, Carboplatin, used in chemotherapy

c. ${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$, Propofol, used to induce anesthesia during surgery

We have to find the molar mass of${\mathrm{CaSO}}_4$

We know that,

Molar mass of one $\mathrm{Ca}$atom =localid="1653485910362" $40.08\mathrm{g}$

Molar mass of one $\mathrm{S}$atom =localid="1653485900062" $32.06\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653485889919" $15.99\mathrm{g}$

So, the molar mass of${\mathrm{CaSO}}_4$=$40.08+32.06+4\left(15.99\right)$=localid="1653485880164" $136.10\mathrm{g}$

We have to find the molar mass of${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$

We know that,

Molar mass of one $\mathrm{C}$atom =localid="1653485924369" $12.01\mathrm{g}$

Molar mass of one $\mathrm{H}$atom =localid="1653485935314" $1.00\mathrm{g}$

Molar mass of one $\mathrm{N}$atom =localid="1653485944647" $14.00\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653485953686" $15.99\mathrm{g}$

Molar mass of one $\mathrm{Pt}$atom = localid="1653485962397" $195.09\mathrm{g}$

So, the molar mass of ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$= $6\left(12.01\right)+12\left(1.00\right)+2\left(14.00\right)+4\left(15.99\right)+195.09$

=localid="1653485972995" $371.11\mathrm{g}$

We have to find the molar mass of${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$

We know that,

Molar mass of one $\mathrm{C}$atom = localid="1653485985918" $12.01\mathrm{g}$

Molar mass of one $\mathrm{H}$atom =localid="1653485994516" $1.00\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653486004544" $15.99\mathrm{g}$

So, the molar mass of${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$=$12\left(12.01\right)+18\left(1.00\right)+15.99$=localid="1653486014010" $178.11\mathrm{g}$