Calculate the mass, in grams, for each of the following:

a. $5.12$ moles of $Al$

b .$0.75$ mole of$Cu$

c. $3.52$ moles of $MgB{r}_2$

d. $0.145$ mole of $C_2{H}_{6}O$

e. $2.08$moles of ${\left(NH4\right)}_{2}S{O}_4$

We need to find the mass in grams

Here one mole is atomic mass of substance expressed in grams .

Here we will use the formula , we are given with the moles and we know molar mass of substance , so we get;

Number of moles=gram molecular weight/molar mass .

Therefore mass of $5.12$mole is$5.12\cancel{moles}\times 26.9\frac{g}{\cancel{moles}}=138$g

We need to find the mass in grams

Here one mole is atomic mass of substance expressed in grams .

Here we will use the formula , we are given with the moles and we know molar mass of substance , so we get;

Number of moles=gram molecular weight/molar mass .

Therefore mass of $0.75$moleslocalid="1653462041856" role="math" $=0.75\cancel{moles}\times 63.54\frac{g}{\cancel{moles}}=47.7$g

We need to find the mass in grams

Here one mole is atomic mass of substance expressed in grams .

Here we will use the formula , we are given with the moles and we know molar mass of substance , so we get;

Number of moles=gram molecular weight/molar mass .

Therefore mass of $3.52$moleslocalid="1653462071079" role="math" $=3.52\cancel{moles}\times 184.1\frac{g}{\cancel{moles}}=648$g

We need to find the mass in grams

Here one mole is atomic mass of substance expressed in grams .

Here we will use the formula , we are given with the moles and we know molar mass of substance , so we get;

Number of moles=gram molecular weight/molar mass .

Therefore mass of $0.145$molelocalid="1653462104779" role="math" $=0.145\cancel{moles}\times 46.07\frac{g}{\cancel{moles}}=6.68015$g

We need to find the mass in grams

Here one mole is atomic mass of substance expressed in grams .

Here we will use the formula , we are given with the moles and we know molar mass of substance , so we get;

Number of moles=gram molecular weight/molar mass .

Therefore mass of $2.08$mole localid="1653462138705" $=2.08\cancel{moles}\times 132.14\frac{g}{\cancel{moles}}=274.8$g