Determine whether each of the following chemical equations are balanced or not balanced:

a.$PC{l}_3\left(s\right)+C{l}_2\left(g\right)\to PC{l}_5\left(s\right)$

b.$CO\left(g\right)+2H_2\left(g\right)\to C{H}_{4}O\left(g\right)$

c.$2KCl{O}_3\left(s\right)\to 2KCl\left(s\right)+O_2\left(g\right)$

d.$Mg\left(s\right)+N_2\left(g\right)\to M{g}_3{N}_2\left(s\right)$

We have been given four equations and we have to check which equation is balanced.

To determine whether or not an equation is balanced, we apply the procedures below:

• Divide each molecule into its constituent atoms. Calculate the number of each type of atom in each molecule.
• Count the number of atoms of each kind on each side of the equation (for the reactants and the result).
• The element is balanced if the number of atoms on both sides of the equation equals one.
• If all of the elements are balanced, the equation is balanced.

We get what we want by following these steps.

$PC{l}_3\left(s\right)+C{l}_2\left(g\right)\to PC{l}_5\left(s\right)$

This reaction is balanced.

We have been given four equations and we have to check which equation is balanced.

To determine whether or not an equation is balanced, we apply the procedures below:

• Divide each molecule into its constituent atoms. Calculate the number of each type of atom in each molecule.
• Count the number of atoms of each kind on each side of the equation (for the reactants and the result).
• The element is balanced if the number of atoms on both sides of the equation equals one.
• If all of the elements are balanced, the equation is balanced.

We get what we want by following these steps.

$CO\left(g\right)+2H_2\left(g\right)\to C{H}_{4}O\left(g\right)$

The reaction is balanced.

We have been given four equations and we have to check which equation is balanced.

To determine whether or not an equation is balanced, we apply the procedures below:

• Divide each molecule into its constituent atoms. Calculate the number of each type of atom in each molecule.
• Count the number of atoms of each kind on each side of the equation (for the reactants and the result).
• The element is balanced if the number of atoms on both sides of the equation equals one.
• If all of the elements are balanced, the equation is balanced.

We get what we want by following these steps.

$2KCl{O}_3\left(s\right)\to 2KCl\left(s\right)+O_2\left(g\right)$

The reaction is not balanced.

The balanced reaction is:

$2KCl{O}_3\left(s\right)\to 2KCl\left(s\right)+3O_2\left(g\right)$

localid="1654094506800" $2{\mathrm{KClO}}_3\left(s\right)⟶2\mathrm{KCl}\left(s\right)+3{\mathrm{O}}_2\left(g\right)$

We have been given four equations and we have to check which equation is balanced.

To determine whether or not an equation is balanced, we apply the procedures below:

• Divide each molecule into its constituent atoms. Calculate the number of each type of atom in each molecule.
• Count the number of atoms of each kind on each side of the equation (for the reactants and the result).
• The element is balanced if the number of atoms on both sides of the equation equals one.
• If all of the elements are balanced, the equation is balanced.

We get what we want by following these steps.

$\mathrm{Mg}\left(s\right)+{\mathrm{N}}_2\left(g\right)⟶{\mathrm{Mg}}_3{\mathrm{N}}_2\left(s\right)$

The reaction is not balanced.

The balanced reaction is: