Ammonia and oxygen react to form nitrogen and water.

4NH3(g)+3O2(g)2N2(g)+6H2O(g)

a. How many grams of O2are needed to react withlocalid="1653487157133" 13.6gof NH3?

b. How many grams of N2can be produced whenlocalid="1653487174328" 6.50gof O2reacts?

c. How many grams of H2Oare formed from the reaction of localid="1653487189643" 34.0gofNH3?

Short Answer

Expert verified

(a) The 19.2g of O2are needed to react with localid="1653487404761" 13.6g of NH3.

(b) The localid="1653487292397" 1.89g of N2can be produced when localid="1653487421465" 6.50g of O2reacts.

(c) The localid="1653487335142" 54g of H2Oare formed from the reaction of34.0g ofNH3.

Step by step solution

01

Part(a) Step 1: Given information

We have to find out how many grams ofO2are needed to react withlocalid="1653487528811" 13.6gofNH3.

02

Part(a) Step 2: Explanation

Now, we solve this question,

68gNH3reacts with 96gO2,

1gNH3reacts with 96g68gO2,

So,13.6gNH3reacts with 96g×13.6g68gO2,

=19.2gO2.

03

Part(b) Step 1: Given information

We have to find out how many grams ofN2can be produced whenlocalid="1653487802710" 6.50gofO2reacts.

04

Part(b) Step 2: Explanation

Now, we solve this question,

96gO2produces 28gN2,

localid="1653487899826" 1gO2produces localid="1653487936104" 28g96gN2,

localid="1653487971697" 6.5gO2produces localid="1653488017810" =28g×6.50g96gN2,

localid="1653488038297" =1.89gN2.

05

Part(c) Step 1: Given information

We have to find out how many grams of H2Oare formed from the reaction of34.0gofNH3.

06

Part(c) Step 2: Explanation

Now, we solve this question,

68gNH3forms 108gH2O,

1gNH3forms 108g68gH2O,

34.0gNH3forms =108g×34g68gH2O,

=54gH2O.

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