In which of the following pairs do both numbers contain the same number of significant figures?

a.$11.0\mathrm{m}\mathrm{and}11.00\mathrm{m}$

b. $0.250\mathrm{m}\mathrm{and}0.205\mathrm{m}$
c. $0.00012\mathrm{s}\mathrm{and}12000\mathrm{s}$

d.$250\mathrm{L}\mathrm{and}2.50\times {10}^{-2}\mathrm{L}$

We need to find that does the both numbers contain same significant figures or not.

Referring to the rules in the significant figure as summarized by the table : $2.2$

There $11.0$has three significant figures- the nonzero digit and the zero at the end. The other number $11.00$have four significant figures- the nonzero digit and the zero at the end. The two number is not the same numbers of significant figures-.

We need to find that does the both numbers contain same significant figures or not.

Referring to the rules in the significant figure as summarized by the table:$2.2$

There $0.0250$has three significant figures- the nonzero digit and the zero at the end. The other number $0.205$have also three significant figures- the nonzero digit and the zero in between nonzero digits.. The two numbers is the same number of significant figures-.

We need to find that does the both numbers contain same significant figures or not.

Referring to the rules in the significant figure as summarized by the table:$2.2$

There $0.00012$has two significant figures- the nonzero digit and all the other zero are place holders. The other number $12000$have also two significant figures- the nonzero digit and the all the other zero are place holders. The two numbers is the same number of significant figures-.

We need to find that does the both numbers contain same significant figures or not.

Referring to the rules in the significant figure as summarized by the table:$2.2$

There $250L$has four significant figures- the nonzero digit and the zero at the end. The other number localid="1653643837999" $2.50\times {10}^{-2}\mathrm{L}$have two significant figures- the nonzero digit. The two number is not the same numbers of significant figures-.