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Chapter 2: Q.2.76 (page 51)

Suppose you have two 100-mL graduated cylinders. In each cylinder, there is 40.0 mL of water. You also have two cubes: one is lead, and the other is aluminum.

Each cube measures 2.0 cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders?
Use table 2.8 for density values.

Short Answer

Expert verified

The final volume is 48 mL.

Step by step solution

01

Given information

Volume of water = 40.0 mL

Density of lead cube = 11.3 g/ml

Density of aluminum cube = 2.70 g/ml

Edge length of cube = 2.0 cm

New water level in each cylinder = ?

02

Simplification

The volume of the cube is given by the formula as:

Volumeofcube=a3

It is given that edge length = 2.0 cm. Thus, the volume will be:

Volumeofcube=a3=(2)3=8cm3

As it is known, 1cm3=1mL

Thus, 8cm3=8mL

The calculation for final volume:

The volume of water is given which is 40.00 mL and the calculated volume is 8 mL.

Thus, the total volume will be:

Totalvolume=40.00mL+8mL=48mL

Hence, the final volume is 48 mL.

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