Draw the Lewis structure for each of the following:

a.${\mathrm{Cl}}_2\mathrm{O}$

b.${\mathrm{H}}_2\mathrm{NOH}$($\mathrm{N}$is the central atom)

c.${\mathrm{H}}_2{\mathrm{CCCl}}_2$

We need to find the Lewis structure of${\mathrm{Cl}}_2\mathrm{O}$

We know that,

$\mathrm{Cl}$belongs to group seven, meaning it possesses seven valence electrons.

$\mathrm{O}$belongs to group six, meaning it possesses six valence electrons.

As a result, the molecule has a total of $20$valence electrons.

$\mathrm{O}$is the center atom because there is only one $\mathrm{O}$in the molecule.

As a result, the molecule's Lewis structure is:

We need to find the Lewis structure of${\mathrm{H}}_2\mathrm{NOH}$

We know that,

$\mathrm{H}$belongs to group one, meaning it possesses one valence electrons.

$\mathrm{O}$belongs to group six, meaning it possesses six valence electrons.

$\mathrm{N}$belongs to group five, meaning it possesses five valence electrons.

As a result, the molecule has a total of $14$valence electrons.

$\mathrm{N}$is the center atom

As a result, the molecule's Lewis structure is:

We need to find the Lewis structure of${\mathrm{H}}_2{\mathrm{CCCl}}_2$

We know that,

$\mathrm{H}$belongs to group one, meaning it possesses one valence electrons.

$\mathrm{Cl}$belongs to group seven, meaning it possesses seven valence electrons.

$\mathrm{C}$belongs to group four, meaning it possesses four valence electrons.

As a result, the molecule has a total of $28$valence electrons.

$\mathrm{C}$is the center atom

As a result, the molecule's Lewis structure is: