Show the dipole arrow for each of the following bonds: $(6.7)$

a.$P-O$

b.$N-F$

c.$O-Cl$

d. $S-Cl$

e.$P-F$

We need to find the dipole arrow of$P-O$.

Here,

Consider bond is $P-O$.

The electronegativity of $P$is $2.1$and the electronegativity of $O$is $3.5$ . Therefore, the arrow should be pointing towards $O$.

Here, the dipole arrow is shown below.

We need to find the dipole arrow of$N-F$.

Here,

Consider bond is $N-F$.

The electronegativity of $N$is $3.0$and the electronegativity of $F$is $4.0$. Therefore , the arrow should be pointing towards $F$.

Here, the dipole arrow is shown below.

We need to find the dipole arrow of$O-Cl$.

Here,

Consider bond is $O-Cl$

The electronegativity of $Cl$is $3.0$and the electronegativity of $O$is $3.5$. Therefore the arrow should be pointing towards $O$.

Here, the dipole arrow is shown below.

We need to find the dipole arrow of$S-Cl$.

Here,

Consider bond is $S-Cl$

The electronegativity of $S$is $2.5$and the electronegativity of $Cl$is $3.0$. Therefore , the arrow should be pointing towards $Cl$.

Here, the dipole arrow is shown below.

We need to find the dipole arrow of$P-F$.

Here,

Consider bond is $P-F$.

The electronegativity of $P$is $2.1$and the electronegativity of $F$is $4.0$. Therefore, the arrow should be pointing towards $F$.

Here, the dipole arrow is shown below.