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Chapter 6: Q. 6.148 (page 210)

Complete the following table for atoms or ions: $(6.1)$

Short Answer

Expert verified

Atom or Ion	Number of protons	Number of electron	Electron loss/ Gained
${Zn}^{2 +}$	$30^{+}$ p	$28 e^{-}$	$2 e^{-}$ lost
$Kr$	$36^{+}$ p	$36 e^{-}$	0
$S^{2 -}$	$16^{+}$ p	$18 e^{-}$	$2 e^{-}$ gained
${Sn}^{4 +}$	$50^{+}$ p	$46 e^{-}$	$4 e^{-}$ lost

Step by step solution

01

Given Information

We need to complete the table.

02

Simplify

Atom or Ion	Number of protons	Number of electron	Electron loss/ Gained
$Z n^{2 +}$	$30^{+} p$	$28 e^{-}$	$2 e^{-} l o s t$
$Kr$	$36^{+} p$	role="math" localid="1652524387565" $36 e^{-}$	$0$
$S^{2 -}$	$16^{+} p$	$18 e^{-}$	$2 e^{-} g a i n e d$
role="math" localid="1652524892187" $S n^{4 +}$	role="math" localid="1652524833052" $50^{+} p$	$46 e^{-}$	$4 e^{-} l o s t$

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Most popular questions from this chapter

Describe the trend in electronegativity as increases or decreases for each of the following:

(a) from B to F

(b) from Mg to Ba

(c) from F to I

Using each of the following electron arrangements, give the formulas for the cation and anion that form, the formula for the compound they form, and its name.

Write the formula for each of the following molecular compounds: $(6.5)$

a. carbon sulfide

b. diphosphorus pentoxide

c. dihydrogen sulfide

d. sulfur dichloride

Compare the Lewis structures of ${CH}_{4}$ and $H_{2} O$ . Why do these molecules have similar bond angles but different molecular shapes?

Identify each of the compounds in problem 6.89 as ionic or molecular.

See all solutions

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