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Chapter 3: Q. 3.20 (page 70)

a. Water is healed to 145∘F. What is the temperature of the hot water in degrees Celsius?

b. During extreme Hypothermia, a child's temperature dropped to 20∘C. What was his temperature in degrees Fahrenheit?

Short Answer

Expert verified

a. The temperature in degrees Celsius is62.7°C

b. The temperature in degrees Fahrenheit is217.4°F

Step by step solution

01

Given Information (a) 

(a) Water is healed to145°F

02

Explanation (a)

(a) Hot water temperature in Fahrenheit is145°F.
The temperature scale and Fahrenheit scale are related as follows:

F=95(C)+32

Substitute the worth of degree Fahrenheit to search out the worth in degree.

∘C=59∘F−32

=59145∘F−32

=59(113)0C

=62.7∘C

Thus, the temperature 145°F is adore the temperature 62.7°C.

03

Given Information (b)

Extreme Hypothermia Child's temperature dropped to20°C

04

Explanation (b)

(b) Body temperature in degree Centigrade is20.6°C
The relationship between temperature scale and Celsius scale is as follows:

F=95(C)+32

Substitute the worth of degree Celsius to seek out the worth in Fahrenheit.

F=95(C)+32

=95(20.6C)+32

=185.4+32

=217.4°F

Thus, the temperature20.6°C is reminiscent of the temperature 217.4°F.

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Most popular questions from this chapter

For lunch, Charles consumed 3oz of skinless chicken, 3oz of broccoli, 1medium apple, and1 cup of nonfat milk (see Table 3.8). How many kilocalories did Charles obtain from the lunch?

Use the heat equation to calculate the energy for each of the following (see Table 3.11 ):

a. calories to heat 8.5g of water from 15∘Cto36∘C

b. joules lost when 25g of water cools from 86∘Cto61∘C

c. kilocalories to heat 150g of water from 15∘Cto77∘C

d. kilojoules to heat 175 g of copper from28∘Cto188∘C

Use the heat equation to calculate the energy, in joules and calories, for each of the following (see Table 3.11):

a. to heat 5.25gof water from 5.5°Cto 64.8C6

b. lost when 75.0gof water cools from86.4°Cto 2.1°C

c. to heat 10.0gof silver from112°Cto 275°C

d. lost when18.0gof gold cools from224°Cto 118°C

In one box of nails, there are 75iron nails weighing 0.250lb. The density of iron is 7.86g/cm3. The specific heat of iron is 0.425J/g∘C. The melting point of iron is 1535∘C..(2.5,2.6,2.7,3.4,3.5)

aWhat is the volume, in cubic centimeters, of the iron nails in the box?

bIf 30 nails are added to a graduated cylinder containing 17.6mLof water, what is the new level of water, in milliliters, in the cylinder?

cHow much heat, in joules, must be added to the nails in the box to raise their temperature from 16∘Cto 125∘C?

dHow much heat, in joules, is required to heat one nail from 25∘Cto its melting point?

What type of change, physical or chemical, takes place in each of the following?

a. Pie dough is rolled into thin pieces for a crust.

b. A silver pin tarnishes in the air.

c. A tree is cut into boards at a saw mill.

d. Food is digested.

e. A chocolate bar melts.
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