Chapter 5: Q. 5.43 (page 160)

Complete the following fission reaction.
${}_{0}^{1}n + {}_{92}^{235}U \to {}_{50}^{131}S n + ? + 2 {}_{0}^{1}n + E n e r g y$

Short Answer

Expert verified

The fission reaction is ${}_{92}^{235}U + {}_{0}^{1}n \to {}_{50}^{131}S n + {}_{42}^{105}M o + 2 {}_{0}^{1}n + E n e r g y$ .

Step by step solution

Introduction

Create a fission reaction that is incomplete.

${}_{92}^{235}U + {}_{0}^{1}n \to {}_{50}^{131}S n + ? + 2 {}_{0}^{1}n + E n e r g y$

Step 2 Determine the mass number that is missing.

$235 + 1 = 131 + ? + 2$

$236 = 133 + ?$

$236 = 131 + ?$

$105 = ?$ (number of new nuclei in mass)

Explanation

Determine the atomic number that is missing.

$92 + 0 = 50 + ? + 0$

$92 - 50 = ?$

$42 = ?$ (new nucleus' atomic number)

Step 4 Determine the new nucleus's symbol - the element with atomic number $42$ on the periodic table is molybdenum, $M o$ ; the symbol for this isotope of $M o$ is written aslocalid="1652247286343" ${}_{42}^{105}M o$

Step 5 Bring the fission reaction to a conclusion.

${}_{92}^{235}U + {}_{0}^{1}n \to {}_{50}^{131}S n + {}_{42}^{105}M o + 2 {}_{0}^{1}n + E n e r g y$

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Complete the following fission reaction.
${}_{0}^{1}n + {}_{92}^{235}U \to {}_{50}^{131}S n + ? + 2 {}_{0}^{1}n + E n e r g y$

Short Answer

Step by step solution

Introduction

Explanation

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Short Answer

Step by step solution

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Explanation

One App. One Place for Learning.

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Complete the following fission reaction.
${}_{0}^{1}n + {}_{92}^{235}U \to {}_{50}^{131}S n + ? + 2 {}_{0}^{1}n + E n e r g y$