Chapter 5: Q. 5.75 (page 165)

If the amount of radioactive phosphorus- $32$ , used to treat leukemia, in a sample decreases from $1.2 mg$ to $0.30 mg$ in $28.6$ days, what is the half-life of phosphorus- $32$ ? $(5.4)$

Short Answer

Expert verified

$1 h a l f - l i f e p e r i o d f o r P - 32 = \frac{28.6 days}{2 half lives} \times 1 h a l f l i f e .$

Phosphorus- $32$ has a half-life of $14.3$ days.

Step by step solution

Given information

Half-life: A radioisotope's half-life is the time it takes for half of a sample to decay. In $28.6$ days, the $P - 32$ sample drops from $1.2 m g$ to $0.30 m g .$

To begin, figure out how many half-lives are needed to reduce the sample from $1.2 m g$ to $0.30 m g$ in $28.6$ days.

$1.2 mg P - 32 \overset{1 half-life}{⟶} 0.6 mg P - 32 \overset{2 half-lives}{⟶} 0.3 mg P - 32$

In $28.6$ days, two half-lives are required to reduce the $P - 32$ sample from $1.2 mg$ to $0.30 mg .$

Explanation

Calculate the half-life of $P - 32$ :

The following are the equality and conversion factors:

$2 half - lives for P - 32 = 28.6 days$

$\frac{28.6 days}{2 half - lives} o r \frac{2 half - lives}{28.6 days}$

Conclusion

Therefore

$1 h a l f - l i f e p e r i o d f o r P - 32$ $= \frac{28.6 days}{2 half lives} \times 1 h a l f l i f e .$

Phosphorus- $32$ has a half-life of $14.3$ days.

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If the amount of radioactive phosphorus- $32$ , used to treat leukemia, in a sample decreases from $1.2 mg$ to $0.30 mg$ in $28.6$ days, what is the half-life of phosphorus- $32$ ? $(5.4)$

Short Answer

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If the amount of radioactive phosphorus-32, used to treat leukemia, in a sample decreases from 1.2mgto 0.30mgin28.6days, what is the half-life of phosphorus-32?(5.4)

Short Answer

Step by step solution

Given information

Explanation

Conclusion

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

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Study anywhere. Anytime. Across all devices.

If the amount of radioactive phosphorus- $32$ , used to treat leukemia, in a sample decreases from $1.2 mg$ to $0.30 mg$ in $28.6$ days, what is the half-life of phosphorus- $32$ ? $(5.4)$