Chapter 5: Q. 5.85 (page 166)

The half-life for the radioactive decay of calcium-47 is $4.5$ days. If a sample has an activity of $1.0 μ Ci$ after 27 days, what was the initial activity, in microcuries, of the sample? $(5.3, 5.4)$

Short Answer

Expert verified

As a result, the product is ${}_{112}^{292}{Fl}$ The following is the whole bombardment reaction $\underset{94}{244} Pu + \frac{48}{20} Ca \to {}_{112}^{292}{Fl}$

Step by step solution

Introduction

To balance a nuclear reaction, both the mass number and the atomic number must balance, which means that the total mass number and atomic number of reactants must equal the result. ${}_{24}^{244}{Pu} + {}_{20}^{+ 8}{Ca} \to$

Mass number of unknown product

The mass number of unknown product:

244 + 48 = A

A = 292

Unknown product's atomic number

The unknown product's atomic number is:

$20 + 94 = Z$

$Z = 114$

Bombardment reaction

As a result, the product is ${}_{112}^{292}{Fl}$ The following is the whole bombardment reaction: $\underset{94}{244} Pu + \frac{48}{20} Ca \to {}_{112}^{292}{Fl}$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

The half-life for the radioactive decay of calcium-47 is $4.5$ days. If a sample has an activity of $1.0 μ Ci$ after 27 days, what was the initial activity, in microcuries, of the sample? $(5.3, 5.4)$

Short Answer

Step by step solution

Introduction

Mass number of unknown product

Unknown product's atomic number

Bombardment reaction

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Kinetics

The Earths Atmosphere

Physical Chemistry

Organic Chemistry

Chemical Reactions

Study anywhere. Anytime. Across all devices.

The half-life for the radioactive decay of calcium-47 is 4.5 days. If a sample has an activity of 1.0μCi after 27 days, what was the initial activity, in microcuries, of the sample? (5.3,5.4)

Short Answer

Step by step solution

Introduction

Mass number of unknown product

Unknown product's atomic number

Bombardment reaction

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Kinetics

The Earths Atmosphere

Physical Chemistry

Organic Chemistry

Chemical Reactions

Study anywhere. Anytime. Across all devices.

The half-life for the radioactive decay of calcium-47 is $4.5$ days. If a sample has an activity of $1.0 μ Ci$ after 27 days, what was the initial activity, in microcuries, of the sample? $(5.3, 5.4)$