Chapter 5: Q.5.79 (page 165)

Write the balanced nuclear equation for each of the following radioactive emissions:
a. an alpha particle from Hg-180
b. a beta particle from Au-198
c. a positron from Rb- 82

Short Answer

Expert verified

Part (a) $_{80}^{180} Hg \to_{78}^{176} Pt +_{2}^{4} He$

Part (b) $_{79}^{198} Au \to_{80}^{198} Hg +_{- 1}^{0} β$

Part (c) $_{37}^{82} R b \to_{36}^{82} Kr +_{+ 1}^{0} e$

Step by step solution

Part (a) Step 1: Given Information

Alpha decay is a typical method of radioactive decay where a core discharges an alpha molecule.

An alpha particle from Hg- $180$ .

Part (a) Step 2: Explanation

The balanced nuclear equation is,

$_{80}^{180} Hg \to_{78}^{176} Pt +_{2}^{4} He$

Part (b) Step 1: Given Information

Beta-decay is a typical method of radioactive decay where a core discharges a beta molecule.

A beta particle from Au- $198$ .

Part (b) Step 2: Explanation

The balanced nuclear equation is,

$_{79}^{198} Au \to_{80}^{198} Hg +_{- 1}^{0} β$

Part (c) Step 1: Given Information

Positron emanation, beta plus decay is a subtype of radioactive decay considered beta decay, in which a proton inside a radionuclide core is changed over into a neutron while delivering a positron and an electron neutrino.

A positron from Rb- $82$

Part (c) Step 2: Explanation

The balanced nuclear equation is,

$_{37}^{82} R b \to_{36}^{82} Kr +_{+ 1}^{0} e$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Write the balanced nuclear equation for each of the following radioactive emissions:
a. an alpha particle from Hg-180
b. a beta particle from Au-198
c. a positron from Rb- 82

Short Answer

Step by step solution

Part (a) Step 1: Given Information

Part (a) Step 2: Explanation

Part (b) Step 1: Given Information

Part (b) Step 2: Explanation

Part (c) Step 1: Given Information

Part (c) Step 2: Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Organic Chemistry

Chemistry Branches

Making Measurements

Nuclear Chemistry

Inorganic Chemistry

Study anywhere. Anytime. Across all devices.

Write the balanced nuclear equation for each of the following radioactive emissions:a. an alpha particle from Hg-180b. a beta particle from Au-198c. a positron from Rb- 82

Short Answer

Step by step solution

Part (a) Step 1: Given Information

Part (a) Step 2: Explanation

Part (b) Step 1: Given Information

Part (b) Step 2: Explanation

Part (c) Step 1: Given Information

Part (c) Step 2: Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Organic Chemistry

Chemistry Branches

Making Measurements

Nuclear Chemistry

Inorganic Chemistry

Study anywhere. Anytime. Across all devices.

Write the balanced nuclear equation for each of the following radioactive emissions:
a. an alpha particle from Hg-180
b. a beta particle from Au-198
c. a positron from Rb- 82