Chapter 9: Q. 9.100 (page 318)

What is the molarity of a solution containing $15.6 g o f K C l$ in $274 m L o f K C l$ solution? $(9.4)$

Short Answer

Expert verified

The optimizer molarity is $0.77 M K C l .$

Step by step solution

Given information

Given $15.6 g K C l$ in a solution of $274 m L = 0.274 .$

Molarity (moles/L) is required.

Compute molarity using the moles of $K C l$ and the quantity of the solution in litres.

$M o l a r i t y (M) = \frac{m o l e s o f s o l u t e}{l i t e r s o f s o l u t i o n}$

$GKCl Molar mass = \frac{moles K C l}{volume (L)} = M K C l solution$

Explanation.

Factors,

$1 m o l e K C l = 74.6 g K C l$

$\frac{1 m o l e K C l}{74.6 g K C l} a n d \frac{74.6 g K C l s s s s}{1 m o l e K C l}$

Equation,

$m o l e s K C l = 15.6 g m L \times \frac{1 m o l e K C l}{74.6 g m L} = 0.21 m o l e s K C l$

Divide the molecules of KCl even by quantity in litres to get the molarity.

$M o l a r i t y = \frac{0.21 m o l e s K C l}{0.274 L} = 0.77 M K C l$

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What is the molarity of a solution containing $15.6 g o f K C l$ in $274 m L o f K C l$ solution? $(9.4)$

Short Answer

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What is the molarity of a solution containing 15.6gofKClin 274mLofKClsolution? (9.4)

Short Answer

Step by step solution

Given information

Explanation.

One App. One Place for Learning.

Most popular questions from this chapter

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What is the molarity of a solution containing $15.6 g o f K C l$ in $274 m L o f K C l$ solution? $(9.4)$