Chapter 9: Q. 9.102 (page 318)

How many milliliters of a $1.50 M N a B r$ solution contain $75.0 g$ of $N a B r$

Short Answer

Expert verified

$486 m l$ of $N a B r$ solution of $1.50 M N a B r$ solution contains $75.0 g$ of $N a B r$

Step by step solution

Given information

To find how much milliliters of $1.50 M N a B r$ solution contains $75.0 g$ of $N a B r$ :

Calculate the moles of NaBr by using the following expression :

Moles of $NaBr = \frac{mass of NaBr}{molar mass of NaBr}$

$= \frac{75 g}{102.89 g / mol}$

$= 0.729 mol$ .

Calculate the volume required by using the following expression :

Volume of $NaBr = \frac{Moles of NaBr}{Molarity of NaBr}$

$= \frac{0.729 mol}{1.50 M}$

$= 0.486 L \times (\frac{1000 mL}{1 L})$

Therefore, the required volume of $N a B r$ solution is $486 m l$ .

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How many milliliters of a $1.50 M N a B r$ solution contain $75.0 g$ of $N a B r$

Short Answer

Step by step solution

Given information

Calculate the moles of NaBr by using the following expression :

Calculate the volume required by using the following expression :

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How many milliliters of a 1.50MNaBrsolution contain 75.0gof NaBr

Short Answer

Step by step solution

Given information

Calculate the moles of NaBr by using the following expression :

Calculate the volume required by using the following expression :

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Chemical Reactions

Making Measurements

Inorganic Chemistry

Kinetics

Nuclear Chemistry

Study anywhere. Anytime. Across all devices.

How many milliliters of a $1.50 M N a B r$ solution contain $75.0 g$ of $N a B r$