Chapter 9: Q. 9.103 (page 318)

How many liters of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ ?

Short Answer

Expert verified

$0.237 L$ of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ .

Step by step solution

Given information

To calculate the how much liters of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ .

To calculate the moles of KNO3 by using the following expression

Moles of ${KNO}_{3} = \frac{mass of {KNO}_{3}}{molar mass of {KNO}_{3}}$

$= \frac{60 g}{101.1 g / mol}$

$= 0.593 mol$ .

To calculate the volume required by using the following expression :

Volume of ${KNO}_{3} = \frac{Moles of {KNO}_{3}}{Molarity of {KNO}_{3}}$

$= \frac{0.593 mol}{2.50 M}$

$= 0.237 L$

Therefore, the required volume of ${KNO}_{3}$ solution is $0.237 L$ .

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How many liters of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ ?

Short Answer

Step by step solution

Given information

To calculate the moles of KNO3 by using the following expression

To calculate the volume required by using the following expression :

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How many liters of a 2.50MKNO3solution can be prepared from60.0gof KNO3 ?

Short Answer

Step by step solution

Given information

To calculate the moles of KNO3 by using the following expression

To calculate the volume required by using the following expression :

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Making Measurements

Chemical Analysis

Physical Chemistry

Chemistry Branches

Kinetics

Organic Chemistry

Study anywhere. Anytime. Across all devices.

How many liters of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ ?